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never [62]
2 years ago
13

What conditions would produce the highest pressure?​

Chemistry
1 answer:
anzhelika [568]2 years ago
3 0

air that is cooling will cause the highest pressure

Explanation:

This is because heat has to escape a certain area and if the heat can't escape then more and more pressure will build up in a area.

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True or False
andrey2020 [161]
False. Electromagnetic and Gravitational forces can overcome .
8 0
3 years ago
Read 2 more answers
How do i balance the first chemical reaction above?? plz plz help
soldier1979 [14.2K]

Answer:

2K +F₂→ 2KF

Explanation:

When we balance an equation, we are trying to ensure that the number of atoms of each element is the same on both sides of the arrow.

On the left side of the arrow, there is 1 K atom and 2 F atoms. On the right, there is 1 K and 1 F atom.

Since the number of K atoms is currently balanced, balance the number of F atoms.

K +F₂→ 2KF

Now, that the number of F atoms is balanced on both sides, check if the number of K atoms are balanced.

<u>Left</u>

K atoms: 1

F atoms: 2

<u>Right</u>

K atoms: 2

F atoms: 2

The number of K atoms is not balanced.

2K +F₂→ 2KF

<u>Left</u>

K atoms: 2

F atoms: 2

<u>Right</u>

K atoms: 2

F atoms: 2

The equation is now balanced.

4 0
3 years ago
13. Find the total number of atoms present in the following molecules. a. 5 H₂O b. Zn Cl₂​
olganol [36]

Answer:

A= 15 atoms B= 3

Explanation:

5 x 2 + 5 x 1

3 + 2 x 1

5 0
3 years ago
Pls help i will mark as brainliest​
oee [108]

Answer:

ano po ito?? isa po ba itong story

8 0
3 years ago
An unknown compound, X is thought to have a carboxyl group with a pKa of 2.0 and another ionizable group with a pKa between 5 an
Westkost [7]

Answer:

7.3

Explanation:

By Henderson Hasselbalch equation we can calculate the pH or the pOH of a solution by its pKa. Remember that pH = -log[H^{+}], and pKa = -logKa. Ka is the equilibrium constant of the acid.

Henderson Hasselbalch equation :

pH = pKa - log \frac{[HA]}{[A^{-}]}

Where [HA] is the concentration of the acid, and [A^{-}] is the concentration of the anion which forms the acid.

So, acid X, has two ionic forms, the carboxyl group and the other one. First, we have 0.1 mol/L of the acid, in 100 mL, so the number of moles of X

n1 = (0.1 mol/L)x(0.1 L) = 0.01 mol

When it dissociates, it forms 0.005 mol of the carboxyl group and 0.005 mol of the other group. Assuming same  stoichiometry.

Adding NaOH, with 0.1 mol/L and 75 mL, the number of moles of OH^- will be

n2 = (0.1 mol/L)x(0.075 L) = 0.0075 mol

So, the 0.0075 mol of OH^- reacts with 0.005 mol of carboxyl, remaining 0.0025 mol of OH^-, which will react with the 0.005 mol of the other group. So, it will remain 0.0025 mol of the other group.

The final volume of the solution will be 175 mL, but both concentrations (the acid form and ionic form) have the same volume, so we can use the number of mol in the equation.

Note that, the number of moles of the acid form is still 0.01 mol because it doesn't react!

So,

6.72 = pKa - log \frac{0.01}{0.0025}

6.72 = pKa - log 4

pKa - log4 = 6.72

pKa = 6.72 + log4

pKa = 6.72 + 0.6

pKa = 7.3

8 0
3 years ago
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