All the answers are correct.
Answer:
4x-11
Step-by-step explanation:
open parentheses: 4x-8-3
solve: 4x-11
\left[x _{2}\right] = \left[ 6+\sqrt{33}\right][x2]=[6+√33]
1. 6:3
2. 6:2
3. 3:18
4:5:6
5:13
6:x
7:x
8: check
9:check
10: x
Number 1 = 17
number 2 = 72
number 3 = 24
work:
the three numbers are symbolized as x, y, and z
x + y + z = 113
number 2 (y) is 3 times the third number (z) so
y = 3z
so x + 3z + z = 113
the first number (x) is 7 less than than the third number (z) so
x = z - 7
so z -7 + 3z + z = 113
5z - 7 = 113
5z = 120
z = 24
x = 17
y = 72
Hope this helped :)