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Murrr4er [49]
3 years ago
14

What will be the resulting equation when you substitute the first equation (-3x + 5) in for y in the second equation?

Mathematics
2 answers:
ANTONII [103]3 years ago
7 0

Answer:

See below.

Step-by-step explanation:

Substituting for y:

5x - 4(-3x + 5) = -3

5x + 12x - 20 = -3

17x = -3 + 20

17x = 17.

x = 1.

Serhud [2]3 years ago
6 0

Answer:

Step-by-step explanation:Substituting for y:

5x - 4(-3x + 5) = -3

5x + 12x - 20 = -3

17x = -3 + 20

17x = 17.

1

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You babysit to make a little extra money. You charge $12 an hour and earned $180 by the end of the month. How many hours did you
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Answer:

The equation is 12x=180. You worked for 15 hours.

Step-by-step explanation:

Do 12x=180 then divide by 12. You get x=180/12. Then simplify

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What is the approximate value for the modal daily sales?
Aleksandr [31]

Answer:

Step-by-step explanation:

Hello!

<em>The table shows the daily sales (in $1000) of shopping mall for some randomly selected  days </em>

<em>Sales 1.1-1.5 1.6-2.0 2.1-2.5 2.6-3.0 3.1-3.5 3.6-4.0 4.1-4.5 </em>

<em>Days 18 27 31 40 56 55 23 </em>

<em>Use it to answer questions 13 and 14. </em>

<em>13. What is the approximate value for the modal daily sales? </em>

To determine the Mode of a data set arranged in a frequency table you have to identify the modal interval first, this is, the class interval in which the Mode is included. Remember, the Mode is the value with most observed frequency, so logically, the modal interval will be the one that has more absolute frequency. (in this example it will be the sales values that were observed for most days)

The modal interval is [3.1-3.5]

Now using the following formula you can calculate the Mode:

Md= Li + c[\frac{(f_{max}-f_{prev})}{(f_{max}-f_{prev})(f_{max}-f_{post})} ]

Li= Lower limit of the modal interval.

c= amplitude of modal interval.

fmax: absolute frequency of modal interval.

fprev: absolute frequency of the previous interval to the modal interval.

fpost: absolute frequency of the posterior interval to the modal interval.

Md= 3,100 + 400[\frac{(56-40)}{(56-40)+(56-55)} ]= 3,476.47

<em>A. $3,129.41 B. $2,629.41 C. $3,079.41 D. $3,123.53 </em>

Of all options the closest one to the estimated mode is A.

<em>14. The approximate median daily sales is … </em>

To calculate the median you have to identify its position first:

For even samples: PosMe= n/2= 250/2= 125

Now, by looking at the cumulative absolute frequencies of the intervals you identify which one contains the observation 125.

F(1)= 18

F(2)= 18+27= 45

F(3)= 45 + 31= 76

F(4)= 76 + 40= 116

F(5)= 116 + 56= 172 ⇒ The 125th observation is in the fifth interval [3.1-3.5]

Me= Li + c[\frac{PosMe-F_{i-1}}{f_i} ]

Li: Lower limit of the median interval.

c: Amplitude of the interval

PosMe: position of the median

F(i-1)= accumulated absolute frequency until the previous interval

fi= simple absolute frequency of the median interval.

Me= 3,100+400[\frac{125-116}{56} ]= 3164.29

<em>A. $3,130.36 B. $2,680.36 C. $3,180.36 D. $2,664</em>

Of all options the closest one to the estimated mode is C.

5 0
3 years ago
(20 points)
chubhunter [2.5K]
V = (1/4)(π* d² * h) 
<span>V = (1/4)(π * 10² * 12) </span>
<span>V = (1/4)(1200π) </span>
<span>V = 300π </span>
<span>[ V ≈ 942 cubic units . . . . . to 3 s.f. ] </span>
<span>V ≈ 942 cubic units 
</span>
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How many students had fewer than 5 buttons on their clothes. <br> a:9 <br> b:18 <br> c:2 <br> d:11
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Answer:

D) 11

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