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NARA [144]
3 years ago
6

A destroyer on patrol spots an aircraft at an altitude of 10,000 ft and an angle of elevation of 20⁰. How far is the aircraft fr

om the ship?
Round to the nearest whole number.
Mathematics
1 answer:
Reika [66]3 years ago
4 0

sin= \frac{opp}{hyp} \\\\sin (20) = \frac{10000}{hyp}\\\\hyp= \frac{10000}{sin(20)} \\\\hyp= 29238 ft

The aircraft is 29238 ft from the ship

//

Note: this is based on my assumption that we are looking for the hypotenuse.

If we are looking for the adjacent side, then the answer would be 27475 ft.

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