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NARA [144]
2 years ago
6

A destroyer on patrol spots an aircraft at an altitude of 10,000 ft and an angle of elevation of 20⁰. How far is the aircraft fr

om the ship?
Round to the nearest whole number.
Mathematics
1 answer:
Reika [66]2 years ago
4 0

sin= \frac{opp}{hyp} \\\\sin (20) = \frac{10000}{hyp}\\\\hyp= \frac{10000}{sin(20)} \\\\hyp= 29238 ft

The aircraft is 29238 ft from the ship

//

Note: this is based on my assumption that we are looking for the hypotenuse.

If we are looking for the adjacent side, then the answer would be 27475 ft.

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Answer:

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Step-by-step explanation:

The sides of all right triangles share the same relationship known as the Pythagorean Theorem a² + b² = c². Substitute the lengths of the triangle into the theorem and solve for the unknown side. Since the problem does have an attached a picture, assume that a = 10, b = 11, and c = x.

10² + 11² = x²

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Marta_Voda [28]

Answer:

<em>No, he should have set the sum of ∠AED and ∠DEC equal to 180°, rather then setting ∠AED and ∠DEC equal to each other</em>

Step-by-step explanation:

Find the diagram attached

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x = 96/16

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Hence the value of x is 6

Hence the correct option is <em>No, he should have set the sum of ∠AED and ∠DEC equal to 180°, rather then setting ∠AED and ∠DEC equal to each other</em>

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