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ollegr [7]
2 years ago
15

The sum of three consecutive even integers is -78, what are the integers ?

Mathematics
1 answer:
Digiron [165]2 years ago
5 0
First, you need to analize and understand the problem, then you must choose and strategy. There is a wide variety of strategies to solve a mathematical problem, in this case, you can use the following, which is based on the information given above:
 1. You have that t<span>he sum of three consecutive even integers is </span>-78<span>, therefore, you can given the variable </span>x&#10;<span> to the first integer, the second even integer is </span>x+2<span> and the third one is </span>x+4&#10;<span>.
 2. Calculate x:
 </span>x+(x+2)+(x+4)=-78<span>
 </span>3x+6=-78
<span> </span>x=-28&#10;<span>
 </span>x+2=-28+2=-26&#10;<span>
 </span>x+4=-28+4=-24&#10;<span>
 Therefore, the answer is:</span>-28,-26,-24&#10;
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Which number produces an irrational number when added to 3/4?
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Any irrational number produces an irrational number when added to 3/4.

This is because 3/4 is rational (it can be represented as a ratio of two integers). You can get an irrational number only when you add rational to irrational (because rational to rational produces a rational sum).
6 0
3 years ago
Gemma’s mum runs the merchandise shop. She buys 60 t-shirts from the wholesaler at £13 each. She sets the selling price of each
SashulF [63]

Answer:

132.6 profit

Step-by-step explanation:

13 plus 30 percent

$16.9 times 40

$676

16.9 - 30%

$11.83 times 20

$236.6 plus 676

$912.6 - 13 × 60

$912.6 - $780

132.6 profit

3 0
2 years ago
Geometry one help please!
12345 [234]
What is the question?
3 0
2 years ago
What's halfway between 3100and4000
Anni [7]
3950 is in between
is the answer
4 0
2 years ago
Read 2 more answers
PLEASE HELP ILL GIVE BRAINLIEST
dusya [7]

1)

(-2+\sqrt{-5})^2\implies (-2+\sqrt{-1\cdot 5})^2\implies (-2+\sqrt{-1}\sqrt{5})^2\implies (-2+i\sqrt{5})^2 \\\\\\ (-2+i\sqrt{5})(-2+i\sqrt{5})\implies +4-2i\sqrt{5}-2i\sqrt{5}+(i\sqrt{5})^2 \\\\\\ 4-4i\sqrt{5}+[i^2(\sqrt{5})^2]\implies 4-4i\sqrt{5}+[-1\cdot 5] \\\\\\ 4-4i\sqrt{5}-5\implies -1-4i\sqrt{5}

3)

let's recall that the conjugate of any pair a + b is simply the same pair with a different sign, namely a - b and the reverse is also true, let's also recall that i² = -1.

\cfrac{6-7i}{1-2i}\implies \stackrel{\textit{multiplying both sides by the denominator's conjugate}}{\cfrac{6-7i}{1-2i}\cdot \cfrac{1+2i}{1+2i}\implies \cfrac{(6-7i)(1+2i)}{\underset{\textit{difference of squares}}{(1-2i)(1+2i)}}} \\\\\\ \cfrac{(6-7i)(1+2i)}{1^2-(2i)^2}\implies \cfrac{6-12i-7i-14i^2}{1-(2^2i^2)}\implies \cfrac{6-19i-14(-1)}{1-[4(-1)]} \\\\\\ \cfrac{6-19i+14}{1-(-4)}\implies \cfrac{20-19i}{1+4}\implies \cfrac{20-19i}{5}\implies \cfrac{20}{5}-\cfrac{19i}{5}\implies 4-\cfrac{19i}{5}

7 0
2 years ago
Read 2 more answers
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