Answer:
The Probability Is That It Has A 50/50 Chance Of Landing On Either Side
Step-by-step explanation:
The answer is 7.5 or 15/2
Using the binomial distribution, it is found that there is a:
a) 0.9298 = 92.98% probability that at least 8 of them passed.
b) 0.0001 = 0.01% probability that fewer than 5 passed.
For each student, there are only two possible outcomes, either they passed, or they did not pass. The probability of a student passing is independent of any other student, hence, the binomial distribution is used to solve this question.
<h3>What is the binomial probability distribution formula?</h3>
The formula is:


The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem:
- 90% of the students passed, hence
.
- The professor randomly selected 10 exams, hence
.
Item a:
The probability is:

In which:




Then:

0.9298 = 92.98% probability that at least 8 of them passed.
Item b:
The probability is:

Using the binomial formula, as in item a, to find each probability, then adding them, it is found that:

Hence:
0.0001 = 0.01% probability that fewer than 5 passed.
You can learn more about the the binomial distribution at brainly.com/question/24863377
Answer:10×12????=120 i think thats what your aski,
Step-by-step explanation:
Answer:
The sample size is 4
Step-by-step explanation:
Null hypothesis: The mean is 2
Alternate hypothesis: The mean is less than 2
Mean = 3
sd = sqrt(variance) = sqrt(4) = 2
At 95% confidence level, t-value is 1.960
Assuming the lower bound of the mean is 1.04
Lower bound = mean - (t×sd/√n)
1.04 = 3 - (1.96×2/√n)
3.92/√n = 3 - 1.04
3.92/√n = 1.96
√n = 3.92/1.96
√n = 2
n = 2^2
n = 4