Answer:
P=88. L=3w
P= 2(w)+2(L)
Then substitute the values into the equation
88=2w+2(3w)
Then solve for w and its length which is 3w
Answer:
173.4
Step-by-step explanation:
Surface area of the cone=pi*r*l+pi*r^2=pi*(4)*(9.8+4)=173.4
Step-by-step explanation:
if the tank is filled with a cap on field to capacity how many half gallons of bottles are filled it will be about well first you have to think how much is half a gallon and it's a half of a gallon is 2 quarts how big is the tank that's what you want to know if you want to fill it up cuz I haven't gotten this 2 quarts tell me how big is the tank
Answer:
I= (x^n)*(e^ax) /a - n/a ∫ (e^ax) *x^(n-1) dx +C (for a≠0)
Step-by-step explanation:
for
I= ∫x^n . e^ax dx
then using integration by parts we can define u and dv such that
I= ∫(x^n) . (e^ax dx) = ∫u . dv
where
u= x^n → du = n*x^(n-1) dx
dv= e^ax dx→ v = ∫e^ax dx = (e^ax) /a ( for a≠0 .when a=0 , v=∫1 dx= x)
then we know that
I= ∫u . dv = u*v - ∫v . du + C
( since d(u*v) = u*dv + v*du → u*dv = d(u*v) - v*du → ∫u*dv = ∫(d(u*v) - v*du) =
(u*v) - ∫v*du + C )
therefore
I= ∫u . dv = u*v - ∫v . du + C = (x^n)*(e^ax) /a - ∫ (e^ax) /a * n*x^(n-1) dx +C = = (x^n)*(e^ax) /a - n/a ∫ (e^ax) *x^(n-1) dx +C
I= (x^n)*(e^ax) /a - n/a ∫ (e^ax) *x^(n-1) dx +C (for a≠0)
