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4 years ago

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1) What is the value of the expression

0-%20%20%7B5%7D%29%5E%7B2%7D%20%20%5Cdiv%204" id="TexFormula1" title="4 + {8}^{3} + 3(9 - {5})^{2} \div 4" alt="4 + {8}^{3} + 3(9 - {5})^{2} \div 4" align="absmiddle" class="latex-formula">

1 answer:

Amanda [17]4 years ago

7 0

4+8³+3(9-5)²÷4=4+512+3×4²÷4=516+3×16÷4=516+48÷4=516+12=528

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Answer:

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Step-by-step explanation:

The graph is in the image

$Midpoint =\left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)\\\\\left(x_1,\:y_1\right)=\left(-3,\:9\right),\:\left(x_2,\:y_2\right)=\left(0,\:1\right)\\\\\left(\frac{0-3}{2},\:\frac{1+9}{2}\right)\\\\Add\:or\:subtract\:the\:numbers\\\\(\frac{-3}{2} , \frac{10}{2}) \\\\Simplify\\\\(-\frac{3}{2} , 5)\\$

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Answer:

The probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.

Step-by-step explanation:

The three different assembly lines are: A₁, A₂ and A₃.

Denote <em>R</em> as the event that a component needs rework.

It is given that:

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$P(R)=P(R|A_{1})P(A_{1})+P(R|A_{2})P(A_{2})+P(R|A_{3})P(A_{3})\\=(0.05\times0.50)+(0.08\times0.30)+(0.10\times0.20)\\=0.069$

Compute the probability that a randomly selected component needs rework when it came from line A₁ as follows:

$P (A_{1}|R)=\frac{P(R|A_{1})P(A_{1})}{P(R)}=\frac{0.05\times0.50}{0.069} =0.3623$

Thus, the probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.

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