So,
We are trying to figure out when Grandpa Lopez's age was twice that of Dad.
Let x represent the number of years before/after when G. Lopez's age was twice that of Dad.
66 + x = 2(37 + x)
Distribute.
66 + x = 74 + 2x
Subtract x from both sides.
66 = 74 + x
Subtract 74 from both sides.
-8 = x
So 8 years ago, G. Lopez was twice as old as Dad. Let's check that.
66 - 8 = 58
37 = 8 = 29
29 * 2 = 58
58 = 58
It checks.
Answer:
-1.5, -1
Step-by-step explanation:
midpoint formula
(x1 + x2 / 2) , (y1 + y2/ 2)
-6 + 3 / 2 , -8 + 6 / 2
Answer:36 16
Step-by-step explanation:
I will go about solving this using the elimination method.
First, convert the equations.
10x + y = -20
4x + y = -12
Second, find the easiest variable to get rid of and get rid of it! (In this case, y) We will subtract to get rid of y.
6x = -8
Third, you want to solve the equation.
6x = -8 (divide by 6)
x =
Fourth, solve for y by inserting the answer for x into one of the equations.
10(
) + y = -20
+ y = -20 (subtract
)
y =
The solution for this system of equations is (
,
).