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Radda [10]
3 years ago
14

Select all of the statistical questions.

Mathematics
1 answer:
Snowcat [4.5K]3 years ago
8 0
b) how many houses are in your town?
c) what percent of long grove high school
students like pizza?
d) what is the average temperature in january?
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HELLLLPPPPPPP PLEASEEEEEE<br> I WILL MARK YOU BRILLLLLLLLL
Annette [7]

Answer:

Answer is 2a + 8 because 2 times a is 2a and 2 times 4 is 8

8 0
3 years ago
Read 2 more answers
What is the value<br> of y when x = 32
musickatia [10]

Answer:

y = 40

Step-by-step explanation:

So, the direct variation equation is y = x.

Substitute 32 for x and find y.

So, y = 40 when x = 32.

8 0
3 years ago
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You are in a bike race. When you get to the first checkpoint, you are 2/5 of the distance to the second checkpoint. When you get
Jobisdone [24]
2/5=8/20
1/4=5/20
     13/20
20/20-13/20= 7/20
7/20 of the distance
3 0
3 years ago
Which equation shows a correct trigonometric ratio for the<br> given figure?
natima [27]

Step-by-step explanation:

sin A = 8/17 (D)

thats all

5 0
3 years ago
Read 2 more answers
Can someone help me with this truth table. I just don't understand how to do it.
RUDIKE [14]

An implication (p\implies q) is true if either the premise (p) is false, or both the premise and conclusion (p\text{ and }q) are both true, and false otherwise.

\begin{array}{c|c|c|c|c|c|c}p&q&p\implies q&\neg q&(p\implies q)\land\neg q&\neg p&(p\implies q)\land\neg q\implies\neg p\\T&T&T&&&&\\T&F&F&&&&\\F&T&T&&&&\\F&F&T&&&&\end{array}

Negation (\neg q) is straightforward; if a statement is true, then its negation is false, and vice versa.

\begin{array}{c|c|c|c|c|c|c}p&q&p\implies q&\neg q&(p\implies q)\land\neg q&\neg p&(p\implies q)\land\neg q\implies\neg p\\T&T&T&F&&F\\T&F&F&T&&F\\F&T&T&F&&T\\F&F&T&T&&T\end{array}

A conjunction (p\land q) is true if both premises are true, and false otherwise.

\begin{array}{c|c|c|c|c|c|c}p&q&p\implies q&\neg q&(p\implies q)\land\neg q&\neg p&(p\implies q)\land\neg q\implies\neg p\\T&T&T&F&F&F\\T&F&F&T&F&F\\F&T&T&F&F&T\\F&F&T&T&T&T\end{array}

Finally, by the rules of implication, we can fill the last column:

\begin{array}{c|c|c|c|c|c|c}p&q&p\implies q&\neg q&(p\implies q)\land\neg q&\neg p&(p\implies q)\land\neg q\implies\neg p\\T&T&T&F&F&F&T\\T&F&F&T&F&F&T\\F&T&T&F&F&T&T\\F&F&T&T&T&T&T\end{array}

5 0
3 years ago
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