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otez555 [7]
3 years ago
12

Find the greatest common factor of 12m^2 and 9b^4

Mathematics
1 answer:
mylen [45]3 years ago
8 0

Answer:

The greatest common factor of 12m^2 and 9b^4 is 3.

I hope this could help, let me know if you need anymore help.

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Suppose f and g are continuous functions such that g(6) = 6 and lim x → 6 [3f(x) + f(x)g(x)] = 45. Find f(6).
aleksandr82 [10.1K]
Since g(6)=6, and both functions are continuous, we have:

\lim_{x \to 6} [3f(x)+f(x)g(x)] = 45\\\\\lim_{x \to 6} [3f(x)+6f(x)] = 45\\\\lim_{x \to 6} [9f(x)] = 45\\\\9\cdot lim_{x \to 6} f(x) = 45\\\\lim_{x \to 6} f(x)=5


if a function is continuous at a point c, then lim_{x \to c} f(x)=f(c), 

that is, in a    c ∈  a continuous interval, f(c) and the limit of f as x approaches c are the same.


Thus, since lim_{x \to 6} f(x)=5, f(6) = 5


Answer: 5


7 0
3 years ago
Evaluate the function:<br><br> f(x)=4x−1, find f(9)
Eddi Din [679]

Answer:

f(9) = 35

Step-by-step explanation:

To solve this, you can take 9 and replace both x's with it and then complete the equation;

f(x) = 4x - 1

f(9) = 4(9) - 1

f(9) = 36 - 1

f(9) = 35

Hope this helps!

3 0
2 years ago
Help me please I really struggling ​
Naya [18.7K]

Answer:

pretty sure the middle is the not in the business class like where f and b meet

8 0
3 years ago
15. A band expects to have 16 songs on their next
stepladder [879]

Answer:

There will be 13 songs in the final album.

Step-by-step explanation:

i) number of songs expected = 16 songs

ii) the band wrrites 62.5% more

   therefore the band writes 16 \times ( 1 + 0.625) = 16 \times 1.625 = 26 songs

iii) During the editing process 50% of the songs are removed.

   Therefore there will be in the final album = ( 1 - 0.5) \times 26  = 0.5 \times 26 = 13 songs.

8 0
3 years ago
The sum of three numbers is 10. Two times the second number minus the first number is equal to 12.
eimsori [14]

<u>Answer:</u>

-10,1,19

<u>Step-by-step explanation:</u>

<u></u>

x+y+z = 10 (Equation 1)

2y-x= 12  (Equation 2)

x-y+2z = 7 (Equation 3)

(Equation 2): -x = -2y+12

                       x = 2y-12 (Equation 4)

(Equation 1) - (Equation 3): 2y-z = 3

                                              -z = -2y+3

                                               z = 2y-3 (Equation 5)

Substitute (4) and (5) into (1)

x+y+z = 10

(2y-12)+y+(2y-3) = 10

5y-15 = 10

5y = 5

y=1

Substitute y=1 into (2)

2y-x= 12

2(1)-x= 12

2-x= 12

-x= 12-2

-x= 10

x= -10

Substitute y=1 and x=-10 into (1)

x+y+z = 10

-10+1+z = 10

z-9 = 10

z = 10+9

z = 19

Order: x = -10, y = 1, and z = 19

8 0
3 years ago
Read 2 more answers
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