<h3>FALSE</h3>
if r < 0, then is alternating
if 0 < r < 1, then is decreases
if r = 1, then is constant
if r > 1, then is icreases
X² + 1 = 0
=> (x+1)² - 2x = 0
=> x+1 = √(2x)
or x - √(2x) + 1 = 0
Now take y=√x
So, the equation changes to
y² - y√2 + 1 = 0
By quadratic formula, we get:-
y = [√2 ± √(2–4)]/2
or √x = (√2 ± i√2)/2 or (1 ± i)/√2 [by cancelling the √2 in numerator and denominator and ‘i' is a imaginary number with value √(-1)]
or x = [(1 ± i)²]/2
So roots are [(1+i)²]/2 and [(1 - i)²]/2
Thus we got two roots but in complex plane. If you put this values in the formula for formation of quadratic equation, that is x²+(a+b)x - ab where a and b are roots of the equation, you will get the equation
x² + 1 = 0 back again
So it’s x=1 or x=-1
Step-by-step explanation:
The rule for a 90 degree counterclockwise is
(x,y) -> (-y,x)
so
C(-1,2) -> C'(-2,-1)
D(3,5) -> D'(-5,3)
E(1,2) -> E'(-2,1)
I don't know if I'm correct, I'm guessing... 30
