Answer:
y = -.5x -.5
Step-by-step explanation:
All you do is plug in the x and y in the point to the equation, y = mx + b. Since the coordinate is (5, -3), this in the equation would look like -3 = -.5(5) +b. (all you need to find is the y-intercept, or b.) Solve it out to get -3 = -2.5 + b. Add 2.5 to each side of the equation, you're left with b = -.5. Now, put that back into the original equation, and get y = -.5x -.5. I think this is right, you can go back through and check once more if you'd like.
Answer:
Option A
Option C
Step-by-step explanation:
A relationship is defined as a function if and only if each element of the "domain" set is assigned only one element of the "range" set. That is, there is only one output value y assigned to each input value x.
The relation x = 3 is not a function because there are infinite output values y, assigned to the same input element x.
(3, 2), (3, 5) (3, 9) (3,10000)
<u><em>Then the option A is true</em></u>
<em><u>Option C is also true,</u></em> the equation of the line shown is

The rest of the options are false because x = 3 is not a function
The answer would be standard deviation.
Answer
f(-4) = 125, g(6) = -13
Step-by-step explanation:
all of those symbols might look really scary, but really all the problem is asking you to do is substitute -4 into the x in f(x) and 6 into the x in g(x) -- basically, f(-4) =
= 125, and g(6) =
= -13. there are your answers!
<span>The answer is: [C]:
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Multiply each side by −8, subtract 35 from each side.
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Explanation:
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Given: You have (-1/8)*(x + 35) = -7
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Note that all the answer choices given start with: "Multiply each side by....";
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Given the choices, multiplying EACH SIDE of the equation by "(-8)" would make sense, since doing would cancel the "(-1/8)" on the "right-hand side" of the equation above to a "1" (i.e "cancel out" that ("-1/8") value); and would result in making the "right side" of the equation above ("-7") a positive integer number.
Then you would be left with: x + 35 = 56 ; so the next step would be to:
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Subtract: "(35)" from each side of the question [hence the answer choice] to isolate "x" on one side of the equation; and to solve for "x".
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