Answer:
Part 1) Helen will need 38 feet of fencing
Part 2) The perimeter around the three sides of the rectangular section of the garden is 27 feet
Part 3) The approximate distance around half of the circle is 11 feet
Step-by-step explanation:
Part 1) How much fencing will Helen need?
Find out the perimeter
we know that
The perimeter of the figure is equal to the sum of three sides of the rectangular section plus the circumference of a semicircle
so

we have

substitute


therefore
Helen will need 38 feet of fencing
Part 2) What is the perimeter around the three sides of the rectangular section of the garden?

we have

substitute


therefore
The perimeter around the three sides of the rectangular section of the garden is 27 feet
Part 3) What is the approximate distance around half of the circle?
Find the circumference of semicircle

we have

substitute


therefore
The approximate distance around half of the circle is 11 feet
Answer:
$ 50,340.97
Step-by-step explanation:
From the above question, we can deduce that we are to find the Initial amount invested which is also called the Principal.
The formula to find Principal in a compound interest question is:
P = A / (1 + r/n)^nt
Where:
A = Total Amount obtained after invested = $80,000
r = Interest rate = 3.1% = 0.031
n = number of times interest in compounded = Quarterly = 4
t = time in years = 15
P = $80,000/(1 + 0.031/4)^4 × 15
P = $80,000/(1 +0.00775)^60
P = $ 50,340.97
Hence, James would have to invest $50,340.97 today to have $80,000 in 15 years.
Step-by-step explanation:
Hey there!
<u>Firstly </u><u>find </u><u>slope </u><u>of</u><u> the</u><u> </u><u>given</u><u> equation</u><u>.</u>
Given eqaution is: 3x + 2y = 5.......(i)
Now;


Therefore, slope (m1) = -3/2.
As per the condition of parallel lines,
Slope of the 1st eqaution (m1) = Slope of the 2nd eqaution (m2) = -3/2.
The point is; (-2,-3). From the above solution we know that the slope is (-3/2). So, the eqaution of a line which passes through the point (-2,-3) is;
(y-y1) = m2 (x-x1)
~ Keep all values.

~ Simplify it.



Therefore, the eqaution of the line which passes through the point (-2,-3) and parallel to 3x + 2y= 5 is 3x + 2y +12 =0.
<em><u>Hope </u></em><em><u>it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
Answer:
3
Step-by-step explanation: