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Ira Lisetskai [31]
2 years ago
5

Next Combining Functions: Mastery Test

Mathematics
1 answer:
dexar [7]2 years ago
6 0

Answer:

D is closest

Step-by-step explanation: Snap add?

1. f(x)*g(x)

\sqrt{x^{2}+12x+36}*x^{3}-12

(x^{2}+2\sqrt{3}x+6)*(x^{3}-12)

(x^{3}-12)(x^{2}+2\sqrt{3}x+6)

(x^{3}-12)(x^{2}+2\sqrt{3}x+6)\\\\x^5+2\sqrt{3}x^4+6x^3-12x^2-24\sqrt{3}x-72\\

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15(2-x)=13(3-x) pls help
schepotkina [342]

Answer:

-4.5

Step-by-step explanation:

15(2-x)=13(3-x)

Expand parentheses:

30-15x=39-13x

Add 15x to both sides:

30=2x+39

Subtract 39 from both sides:

2x=-9

Divide both sides by 2:

x=-4.5

Hope this helps!

6 0
3 years ago
Read 2 more answers
A book designer decided that the pages of a book should have 1-in. margins at the top and bottom and 1 2 in. margins on the side
alexgriva [62]

Answer:

A = 54.8 - (1200/x) - 2x

Step-by-step explanation:

Given <em>x</em> the wide and <em>y</em> the height, we have

x*y = 50

⇒  y = 50/x

The area of the printed region is A = w*h

where

Wide: w = (x-2*1.2) = x-2.4

Height: h= (y-2*1) = y-2

then

A = (x-2.4)(y-2) = xy - 2.4y - 2x + 4.8 = 50 - 24*(50/x) - 2x + 4.8

⇒  A = 54.8 - (1200/x) - 2x

5 0
3 years ago
1 - 2x = -x - 3 what is the answer?
cricket20 [7]
Isolate the variable x.
 1-2x=-x-3
1=x-3
x=4
4 0
2 years ago
Read 2 more answers
13 Pts<br><br> PLEASE SOMEONE HELP ME WITH THIS QUESTION<br> PLZ EXPLAIN<br><br> THANK U
AlexFokin [52]
It's the third one and the last one are the only ones that make immediate sense.
4 0
3 years ago
Read 2 more answers
If $x$ is the average of $13$, $-16$, and $6$ and if $y$ is the cube root of $8$, find $x^2 + y^3$. Please Help
Alekssandra [29.7K]

Answer:

If we have a set of N elements:

{x₁, x₂, ..., xₙ}

The mean value (also called the average value) Is calculated as:

Average = (x₁ + x₂ + ... + xₙ)/n

So if x is the average of 13, -16 and 6 ( a total of 3 values)

x will be equal to:

x = (13 + (-16) + 6)/3 = (19 - 16)/3 = 3/3 = 1

x = 1

And we know that:

y = ∛8

Remember that:

2*2 = 4

and

4*2 = 8

then

2*2*2 = 2^3 = 8

then ∛8 = 2.

So we have:

y = ∛8 = 2

Now we can replace these values in the equation:

x^2 + y^3

replacing:

x = 1

y = 2

we get:

1^2 + 2^3 = 1 + 8 = 9

5 0
2 years ago
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