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faltersainse [42]
3 years ago
14

Approximate square root 800 to the nearest tenth

Mathematics
2 answers:
snow_tiger [21]3 years ago
5 0
15.29 hope this is right good luck
andrezito [222]3 years ago
3 0
Yeah I think 15.29 as well
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Solve this system of linear equations. Separate
tia_tia [17]

Answer:

(9,4)

Step-by-step explanation:

The given system is:

9x + 3y = 93

3x - 4y = 11

Multiply the bottom equation by 3 to get:

9x + 3y = 93

9x - 12y = 33

Subtract bottom equation from top one to get:

3y--12y=93-33

15y = 60

y =  \frac{60}{15}

y = 4

We put y-value into the bottom equation:

3x - 4 \times4= 11

3x - 16= 11

3x = 11 + 15

3x = 27

x =  \frac{27}{3}

x = 9

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3 years ago
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nydimaria [60]

Answer:

False

Step-by-step explanation:

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3 years ago
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Sav [38]

Answer:

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7 0
3 years ago
A(5 1) b(1 5) and c(-3 -1) are the vertices of triangle abc. find the LENGTH of median ad
faltersainse [42]

Answer:

\text{Length of median AD}=\sqrt{37}

Step-by-step explanation:

We are given the vertices of triangle ABC. We need to find the length of median AD.

Please see the attachment for figure.

D is mid point of BC because median bisect the opposite side of triangle.

Using the formula of mid point. we get coodrinate of D

\text{Mid Point :}\left ( \frac{x_1+x_2}{2},\frac{y_1+y_2}{2} \right )

D is mid point of B(1,5) and C(-3,-1)

\therefore D \left ( \frac{1-3}{2},\frac{5-1}{2} \right )\Rightarrow (-1,2)

AD is median of triangle ABC. Now we find length of median AD using distance formula of two coordinate.

\text{Distance }=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

A(5,1) and D(-1,2)

AD=\sqrt{(5+1)^2+(1-2)^2}\Rightarrow \sqrt{36+1}

\text{Length of median AD}=\sqrt{37}

Thus, \text{Length of median AD}=\sqrt{37}

8 0
3 years ago
A teacher recorded the time, in minutes, it took each student in two classes to complete a quiz. The results are shown in the bo
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4 0
3 years ago
Read 2 more answers
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