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faltersainse [42]
3 years ago
14

Approximate square root 800 to the nearest tenth

Mathematics
2 answers:
snow_tiger [21]3 years ago
5 0
15.29 hope this is right good luck
andrezito [222]3 years ago
3 0
Yeah I think 15.29 as well
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Complete the following table for residuals for the linear function f(x) = 138.9x − 218.76. (Round to the hundredths place)
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<em>Answer:</em>

<h3><em>i believe it is 65 if it isnt then idk</em></h3>

<em>Step-by-step explanation:</em>

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Question 2..plz help meee​
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refer to the attachment

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2 years ago
Find the circumference of a pizza with a diameter of 18 inches
tatyana61 [14]
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8 0
2 years ago
Hi. Please I need help with these questions.
ElenaW [278]

Answer:

Q 12 roots of the equation

2x^{2} -6+1=0 \\= (x-\frac{\sqrt{10} }{2})(x+\frac{\sqrt{10} }{2})\\

∝ = \frac{\sqrt{10} }{2}

β = -\frac{\sqrt{10} }{2}

no matter if u oppose the root

(i) 2(\frac{\sqrt{10} }{2})(-\frac{\sqrt{10} }{2} )^{2}+2(\frac{\sqrt{10} }{2} )^{2}(-\frac{\sqrt{10} }{2})+2(

(ii)((\frac{\sqrt{10} }{2})^{2} - 3 (\frac{\sqrt{10} }{2})(-\frac{\sqrt{10} }{2}) + ((-\frac{\sqrt{10} }{2})^{2}) = \frac{25}{2}

Q 13  roots of equation

4x^{2} -3x-4=0\\\alpha = -0.693\\\beta = 1.443

the roots of the second equation are

x1 = 1/3(-0.693) = -0.231

x2 = 1/3(1.443) = 0.481

the equation is

(x+0.231)(x-0.481)=0

x^{2}-\frac{1}{4} x-\frac{1}{9}

4 0
3 years ago
Can someone do help with any of these please?
laiz [17]
39.

|z+7|=12/3
|z+7|=4
z+7=4
-(z+7)=4
solve the first equation:
z+7=4
z=-3
solve the second equation:
-(z+7)=4
z=-11

z=-11,-3

8 0
2 years ago
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