Answer:
z = 21 ; y= 16
Step-by-step explanation:
first of all we have to isolate a variable.
In second expression we can obtain:
3y = 2z+6
y = 2/3 z + 2
now we have to substitute this value in the first equation and solve it
8(2/3z+2)-5z = 23
16/3z + 16 -5z = 23
16z +48 - 15z = 69
z = 21
now we have to substitute z in the second equation:
y = 2/3 (21) +2
y = 14+ 2 = 16
y = 16
Answer:
Ruth is x+4=7/3+4, esmerelda is 5x+4=35/3+4
Step-by-step explanation:
if Ruth is x, esmerelda is 5x,
four years ago,
Ruth is x+4, esmerelda is 5x+4, depend on the sum, we get:
x+4+5x+4=22, x=7/3
so:
Ruth is x+4=7/3+4, esmerelda is 5x+4=35/3+4
Step-by-step explanation:
if tyler is 7kg
frazer is 23-7kg
so he is 16kg
Answer:
nuber 1
Simplifying
3x + 2y = 35
Solving
3x + 2y = 35
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-2y' to each side of the equation.
3x + 2y + -2y = 35 + -2y
Combine like terms: 2y + -2y = 0
3x + 0 = 35 + -2y
3x = 35 + -2y
Divide each side by '3'.
x = 11.66666667 + -0.6666666667y
Simplifying
x = 11.66666667 + -0.6666666667y
Answer:
the relation between them are
n(U) = n(X U Y) + n(xūy).
