72.22 I think I’m sorry if I’m wrong
<u>Given</u>:
Given that the data are represented by the box plot.
We need to determine the range and interquartile range.
<u>Range:</u>
The range of the data is the difference between the highest and the lowest value in the given set of data.
From the box plot, the highest value is 30 and the lowest value is 15.
Thus, the range of the data is given by
Range = Highest value - Lowest value
Range = 30 - 15 = 15
Thus, the range of the data is 15.
<u>Interquartile range:</u>
The interquartile range is the difference between the ends of the box in the box plot.
Thus, the interquartile range is given by
Interquartile range = 27 - 18 = 9
Thus, the interquartile range is 9.
Answer:
31.85
Step-by-step explanation:
to subtract 30 percent from 45.50 just divide the percentage (30) by 100 subtract this value form 1 then multiply it by the initial value (45.50) so
final value = 45.50 x ( 1 - 
)
final value = 45.50 x ( 1 - 0.3)
final value = 45.50 x (0.7)
final value = 31.85
subtract 30% is the same as discount 30% this operation could be for example a 30% discount on 45.50
note: 0.3 can be found just by moving the decimal point 2 places to the left = 0.3 as a decimal
The answer is 73.5
To make it a lot easier split the shapes into a rectangle and triangle.
The rectangle is a tad easier because the measurements are given here.
5 x 12 = 60 (rectangle area)
To find the triangle find the base then height. The base is 3cm and the height is 9cm (shown above)
9 x 3 = 27
Divide that by 2 because it's a triangle and you get 13.5.
Add those two numbers and voila you have your answer of 73.5.
