I believe “NK” is not a line segment
Since 3=30/10, (30+1)/10=31/10. 31s/10=(30+1)/5 ( we get 30 because 5*6=30) = 31/5. Multiplying both sides by 10, we get 31s=62 (since 5 is a factor of 10, we can do 10/5 =2 and multiply 2 by 31). Dividing both sides by 31, we get s =2
Answer:dy/dx=3x^2 + 2
Step-by-step explanation:
y=x^3 + 2x - 1
dy/dx=3x^2 + 2
Answer:
2-square root 3, 2+ square root 3
Step-by-step explanation:
If the polynomial has rational and real coefficients, the roots will be "conjugates" of each other. That is, the sum of the root should be a rational number. So, the irrational parts will be opposites, while the rational parts remain the same.
2±√3 . . . can be the roots of p(x) when p(x) has rational real coefficients
