Answer:
7m^4-52m^3-28m^2+67m+42
Step-by-step explanation:
(7m^2-3m-7)(m^2-7m-6)
7m^4-3m^3-7m^2-49m^3+21m^2+49m-42m^2+18m+42
7m^4-3m^3-49m^3-7m^2+21m^2-42m^2+49m+18m+42
7m^4-52m^3-28m^2+67m+42
Answer: The answer is 381.85 feet.
Step-by-step explanation: Given that a window is 20 feet above the ground. From there, the angle of elevation to the top of a building across the street is 78°, and the angle of depression to the base of the same building is 15°. We are to calculate the height of the building across the street.
This situation is framed very nicely in the attached figure, where
BG = 20 feet, ∠AWB = 78°, ∠WAB = WBG = 15° and AH = height of the bulding across the street = ?
From the right-angled triangle WGB, we have

and from the right-angled triangle WAB, we have'

Therefore, AH = AB + BH = h + GB = 361.85+20 = 381.85 feet.
Thus, the height of the building across the street is 381.85 feet.
Answer:
0 (1,2,3,4,5,)and (0,1,2,3,4,5,)
Answer:
Depending on the equation it will change
n=1 (not in an equation)
Step-by-step explanation:
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