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german
3 years ago
5

Could anybody explain simplifying fractions to me with an example?

Mathematics
1 answer:
mars1129 [50]3 years ago
3 0

search it up on or something

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Quadrilateral STAY is dilated to quadrilateral WOKE. If S is located at (6, 3) ) and W is located at (3, 3/2) , which rule repre
galben [10]

Answer:

S(x, y) → W(\frac{1}{2}x,\frac{1}{2}y)

Step-by-step explanation:

Quadrilateral STAY has been dilated to quadrilateral WOKE.

Coordinates of the S are (6, 3) and after dilation coordinates of the point W are (3, \frac{3}{2}).

Scale factor for dilation = \frac{\text{Coordinates of image}}{\text{Coordinates of actual}}

                                       = \frac{3}{6}

                                       = \frac{1}{2}

So quadrilateral STAY has been dilated by a scale factor of \frac{1}{2} to form WOKE.

Therefore, rule for the dilation will be,

S(x, y) → W(\frac{1}{2}x,\frac{1}{2}y)

7 0
3 years ago
Que expresión representa el teorema de Pitágoras
Likurg_2 [28]
La Respuesta es B. A2+B2=C2
4 0
3 years ago
Find the geometric mean between each pair of numbers 8 and 12
rodikova [14]

Step-by-step explanation:

......................................................

8 0
3 years ago
I really need help with these questions:
slava [35]
If we take the Pythagorean identity identity sin^2 x + cos^2 x = 1 then
                          <span>(cos^2 x + sin^2 x) / (cot^2 x - csc^2 x)
The numerator becomes 1 since addition order matters not.
                                                 1 / </span>(cot^2 x - csc^2 x)
If we factor the denominator out a negative
                                                1 / -(<span>csc^2 x - cot^2 x)
Consider </span><span>sin^2 x + cos^2 x = 1. Divide both sides by sin^2 x to get
                                         1 + cot^2 x = csc^2 x
Subtract both sides by cot^2 x to get 1 = csc^2 x - cot^2 x.
Replace the denominator
                                                 1 / -(1) = -1
For cos</span>^2 θ / sin^2 θ + csc θ sin θ, we use cscθ = 1/sinθ and cosθ/sinθ = cotθ so
                                = cos^2 θ / sin^2 θ + 1
                                = cot^2 θ + 1
We use 1 + cot^2 <span>θ = csc^2 </span>θ to simplify this to
                              = csc^2 θ

Answers:         -1
                          csc^2 θ
5 0
3 years ago
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Solce for y 5×+y=-10
horrorfan [7]

Answer:x =2

Step-by-step explanation:

7 0
4 years ago
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