Answer:
y - 2 = 3(x + 5)
Step-by-step explanation:
The given equation has slope -1/3. Any line perpendicular to the given line has a slope which is the negative reciprocal of -1/3, which comes out to +3.
Use the point-slope formula y - k = m(x - h):
y - 2 = 3(x + 5)
Answer:
Step-by-step explanation:
hypotenuse=2*AB
where AB is the smallest side.
Take AB as the base .
Draw a perpendicular at B.
A as the center and cut an arc AC=2 AB
Join AC.
CAB is the reqd. triangle.
The given equation is
where h is the height, in feet, of a ball and t is the time, in seconds.
<u>Part a: The height of the ball when t = 2 seconds:</u>
The height of the ball above the ground 2 seconds after it is released can be determined by substituting t= 2 in the equation
, we get;
![h(2)=-16(2)^2+80(2)+4](https://tex.z-dn.net/?f=h%282%29%3D-16%282%29%5E2%2B80%282%29%2B4)
Simplifying the terms, we get;
![h(2)=-64+160+4](https://tex.z-dn.net/?f=h%282%29%3D-64%2B160%2B4)
![h(2)=100](https://tex.z-dn.net/?f=h%282%29%3D100)
Thus, the height of the ball after 2 seconds is 100 feet.
<u>Part b: The height of the ball when t = 4 seconds:</u>
The height of the ball above the ground 4 seconds after it is released can be determined by substituting t = 4 in the equation
, we get;
![h(4)=-16(4)^2+80(4)+4](https://tex.z-dn.net/?f=h%284%29%3D-16%284%29%5E2%2B80%284%29%2B4)
Simplifying the terms, we get;
![h(4)=-256+320+4](https://tex.z-dn.net/?f=h%284%29%3D-256%2B320%2B4)
![h(4)=68](https://tex.z-dn.net/?f=h%284%29%3D68)
Thus, the height of the ball after 4 seconds is 68 feet.