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Verizon [17]
3 years ago
9

DAILY REMINDER ~ YOU ARE LOVED BY SOMEONE I HOPE YOU HAVE A WONDERFUL DAY BABES!

Chemistry
2 answers:
zhuklara [117]3 years ago
7 0

thank you

so much i hope you have a great day aswell

Mila [183]3 years ago
3 0

Answer:

THANK YOU

YOU TOO!

Explanation:

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Standard reduction potentials are based on which element?
KonstantinChe [14]
They're based on hydrogen.
6 0
3 years ago
Read 2 more answers
Do all titrations of a strong base with a strong acid have the same ph at the equivalence point?
Luba_88 [7]

Answer:

  • <u>Yes,</u> <em>all titrations of a strong base with a strong acid have the same pH at the equivalence point.</em>

       This <u>pH is 7.</u>

Explanation:

<em>Strong acids</em> and <em>strong bases</em> ionize completely in aqueous solutions. The ionization of strong acids produce hydronium ions, H₃O⁺, and the ionization of strong bases produce hydroxide ions, OH⁻.

Since the ionization of strong acids and bases progress until completion, there is not reverse reaction.

The definition of pH is pH = - log [H₃O⁺]. Acids have low pH (below 7, and greater than 0) and bases have high pH (above 7 and less than 14). Neutral solutions have pH = 7.

Acid-base titrations are a method to determine the concentration of an acid from the known concentration of a base, or the concentraion of a base from the known concentration of an acid.

The<em> equivalence point</em> of the titration is the point at which the the number of moles of hydronium ions and hydroxide ions are equal.

Then, at that point, the hydronium and hydroxide ions will be in the stoichiometric proportion to form a neutral solution, i.e. the pH of the solution wiill be 7.

7 0
3 years ago
Which of the following statements best describes why a solution of 6.00 g of Ca(NO3)2?in 30.0 g of water has a greater boiling-p
sukhopar [10]
Boiling-point elevation is a colligative property.

That means, the the boiling-point elevation depends on the molar content (fraction) of solute.

The dependency is ΔTb = Kb*m

Where ΔTb is the elevation in the boiling point, kb is the boiling constant, and m is the molality.

A solution of 6.00 g of Ca(NO3) in 30.0 g of water has 4 times the molal concentration of a solution of 3.00 g of Ca(NO3)2 in 60.0 g of water.:

(6.00g/molar mass) / 0.030kg = 200 /molar mass
(3.00g/molar mass) / 0.060kg =   50/molar mass

=> 200 / 50 = 4.

Then, given the direct proportion of the elevation of the boiling point with the molal concentration, the solution of 6.00 g  of CaNO3 in 30 g of water will exhibit a greater boiling point elevation.

Or, what is the same, the solution with higher molality will have the higher boiling point.
5 0
3 years ago
How many grams of KCIO3 will be formed from 3.58g of KCI
blsea [12.9K]

Answer:

5 mols

Explanation:

7 0
3 years ago
Use the limiting reagent to determine how many grams of Cu(OH)2 should precipitate out in the reaction - CuSo4(aq) + 2NaOH(aq) -
Elis [28]
I think there is a lack of information in the given problem above such as the grams of copper sulfate and sodium hydroxide that was used in the experiment. Kindly resubmit the question with the complete details so that we can help you. Thank you.

7 0
3 years ago
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