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Anuta_ua [19.1K]
2 years ago
5

Determine the element symbol, mass number, and charge for an atom or ion that has a 51 neutrons, 38 protons, and 36 electrons.

Chemistry
1 answer:
amid [387]2 years ago
3 0

Answer:

Strontium

Explanation:

To find the element, we need to know the atomic number. There is this rule in chemistry that says that the number of protons and the atomic number are the same. Since we know that there are 38 protons, the atomic number is also 38, leading us to Strontium. Sr -- element symbol.

The mass number is located below the element symbol on a periodic table. The mass number or the atomic mass for Strontium is 87.62 u.

Since there are an uneven amount of protons and electrons, let's subtract the number of electrons from the number of protons to find the difference. 38-36 = 2. (Also, protons are positive and electrons are negative, meaning there are more + than - in the ionic charge). Which means, the atom has a +2 ionic charge.

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Answer:

The oxidation state of N in the KNO3 is +5

Explanation:

Oxidation rules:

1. Oxygen is -2, unless in peroxides.

2. Group 1 metals = +1

3. Group 2 metals = +2

4. If the molecule is neutral, all of the oxidation numbers have to add up to zero.

5. If the molecule is charged, all of the oxidation numbers have to add up to the charge of the molecule.  

So, the given formula represents the salt compound formula unit of potassium nitrate:  KNO3  

The formula unit is uncharged.

From our rules, we know that,

O = -2

And we can find K on the periodic table, in the first group, thus giving it a +1 charge. Now let's put it all together.

K = +1

N = x

O = -2

Let's take into account the number of atoms of each element we have and make an equation since we know everything has to add up to zero since the molecules are neutral.

+1 +x+3 (-2) = 0 (notice we multiplied 3 by -2 because in the formula we have 3 atoms of oxygen with -2 charge each)

x - 5 = 0

x = 5

Therefore, the oxidation number of N in KNO3 is +5.

5 0
3 years ago
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kolbaska11 [484]

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Explanation:

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GenaCL600 [577]
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