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3 years ago

Determine the element symbol, mass number, and charge for an atom or ion that has a 51 neutrons, 38 protons, and 36 electrons.

Chemistry

1 answer:

amid [387]3 years ago

3 0

Answer:

Strontium

Explanation:

To find the element, we need to know the atomic number. There is this rule in chemistry that says that the number of protons and the atomic number are the same. Since we know that there are 38 protons, the atomic number is also 38, leading us to Strontium. Sr -- element symbol.

The mass number is located below the element symbol on a periodic table. The mass number or the atomic mass for Strontium is 87.62 u.

Since there are an uneven amount of protons and electrons, let's subtract the number of electrons from the number of protons to find the difference. 38-36 = 2. (Also, protons are positive and electrons are negative, meaning there are more + than - in the ionic charge). Which means, the atom has a +2 ionic charge.

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4 years ago

If Marie and Calvin dissolve 50 grams of KBr in 100 grams of water at 90oC, the solution is

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3 years ago

A phosphate buffer is involved in the formation of urine. The developing urine contains H2PO4 and HPO42- in the same concentrati

Katen [24]

Answer:

The ionization equation is

$H_{2}PO_{4}^{-} +H_{2}O$ ⇄ $HPO_{4}^{-2} +H_{3}O^{+}$ (1)

Explanation:

The ionization equation is

$H_{2}PO_{4}^{-} +H_{2}O$ ⇄ $HPO_{4}^{-2} +H_{3}O^{+}$ (1)

As the Bronsted definition sais, an acid is a substance with the ability to give protons thus, H2PO4 is the acid and HPO42- is the conjugate base.

The Ka expression is the ratio between the concentration of products and reactants of the equilibrium reaction so,

$Ka = \frac{[HPO_{4}^{-2}] [H_{3}O^{+}]}{[H_{2}PO_{4}^{-}] [H_{2}O]} = 6.2x10^{-8}$

The pKa is

$-Log (Ka) = -Log (6.2x10^{-8}) = 7.2$

The pKa of H2CO3 is 6,35, thus this a stronger acid than H2PO4. The higher the pKa of an acid greater the capacity to donate protons.

In the body H2CO3 is a more optimal buffer for regulating pH due to the combination of the two acid-base equilibriums and the two pKa.

If the urine is acidified, according to Le Chatlier's Principle the equilibrium (1) moves to the left neutralizing the excess proton concentration.

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4 years ago