Answer:
<em>17500 calories</em> of chocolate bars are needed to eat to gain 5 pounds.
Explanation:
We can use ratios to calculate the answer using the information given in the question.
1 pound : 3500 grams
5 pounds : x grams
As it is given that the individual is burning no calories, we do not have to factor in any additional numbers.
<u><em>Method</em><em> </em><em>A</em><em>:</em></u>
To go from 1 in the first ratio to 5 in the second ratio, they multipled 1 by 5. Hence, to go from 3500 in the first ratio to x in the second ratio, we must multiply by 5.
x = 3500 × 5
x = 17500
<em><u>Method B</u>:</em>
To solve for the answer x, we can convert the ratios into fractions.
1 / 5 = 3500 / x
3500 / x = 1 / 5
To make x the subject, multiply the denominator of the left fraction with the numerator of the right fraction and place it on the left side. Then multiply the numerator of the left fraction with the denominator of the right fraction and place it on the right side.
x = 5 × 3500
x = 17500
Answer:
B Two
Explanation:
Let's check it out
H2SO4
hydrogen has one molecule
sulphur has 1
oxygen has -2
c. alpha ; neutrino. Hope it helps
Answer:
temperatures within the outer core range from 7,200 to 9,000 F. Pressure also increases in the outer core due in part to the weight of the crust and mantle above.The Earth's magnetic field is generated by the outer core.
Explanation:
The rate of effusion of H₂ : 7.2 x 10⁻² m/s
<h3>Further explanation </h3>
Graham's law: the rate of effusion of a gas is inversely proportional to the square root of its molar masses or
the effusion rates of two gases = the square root of the inverse of their molar masses:
![\rm \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }](https://tex.z-dn.net/?f=%5Crm%20%5Cdfrac%7Br_1%7D%7Br_2%7D%3D%5Csqrt%7B%5Cdfrac%7BM_2%7D%7BM_1%7D%20%7D)
or
![\rm M_1\times r_1^2=M_2\times r_2^2](https://tex.z-dn.net/?f=%5Crm%20M_1%5Ctimes%20r_1%5E2%3DM_2%5Ctimes%20r_2%5E2)
MW₁ O₂ = 32 g/mol
MW₂ H₂ = 2 g/mol
![\tt \dfrac{1.8\times 10^{-2}}{r_2}=\sqrt{\dfrac{2}{32} }\\\\\dfrac{(1.8\times 10^{-2})^2}{r_2^2}=\dfrac{2}{32}\\\\r_2=0.072=7.2\times 10^{-2}~m/s](https://tex.z-dn.net/?f=%5Ctt%20%5Cdfrac%7B1.8%5Ctimes%2010%5E%7B-2%7D%7D%7Br_2%7D%3D%5Csqrt%7B%5Cdfrac%7B2%7D%7B32%7D%20%7D%5C%5C%5C%5C%5Cdfrac%7B%281.8%5Ctimes%2010%5E%7B-2%7D%29%5E2%7D%7Br_2%5E2%7D%3D%5Cdfrac%7B2%7D%7B32%7D%5C%5C%5C%5Cr_2%3D0.072%3D7.2%5Ctimes%2010%5E%7B-2%7D~m%2Fs)