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3 years ago

. Which algebraic expression is equivalent to the expression below?

1 answer:

5 0

Since you are not distributing at all, you can ignore the parenthesis :)

When ignoring the parenthesis your equation is
18x + 11 - 4x

Then just combine like terms :)

14x + 11

Your answer is C.

Hope this helped!

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Clarice Sloan is a shift supervisor for Ace

Igoryamba

The net pay is the amount left after taxes and deductions have been removed from the gross pay.

Her monthly gross pay is: $4111.93

The deductions are:

$\mathbf{FIT = \$102}$

$\mathbf{SIT = 3.2\%}$

$\mathbf{CIT = 1.8\%}$

Let her gross pay be x.

So, we have:

$\mathbf{Net = x - FIT - x \times SIT - x \times CIT}$

So, we have:

$\mathbf{3804.33 = x - 102 - x \times 3.2\%- x \times 1.8\%}$

Express percentage as decimals

$\mathbf{3804.33 = x - 102 - x \times 0.032- x \times 0.018}$

$\mathbf{3804.33 = x - 102 - 0.032x - 0.018x}$

Add 102 to both sides

$\mathbf{3906.33 = x - 0.032x - 0.018x}$

$\mathbf{3906.33 = 0.95x}$

Divide both sides by 0.95

$\mathbf{4111.93 = x}$

Rewrite as:

$\mathbf{x = 4111.93 }$

Hence, her monthly gross pay is: $4111.93

Read more about gross and net pay at:

brainly.com/question/8952173

4 0

3 years ago

Find the length of the side f .

algol13

I am pretty sure the answer is 10. Someone correct me if I'm wrong
$10 {}^{2} + 15 {}^{2} = 18 {}^{2} \\ 100 + 225 = 325 \\ \sqrt{325} = 18$

3 0

3 years ago

Read 2 more answers

Find the least common multiple (LCM) of 8y^6+ 144y^5+ 640y^4 and 2y^4 + 40y^3 + 200y^2.

Mice21 [21]

Answer:

LCM = $8y^{4}(y+ 10)^{2}(y + 8)$

Step-by-step explanation:

Making factors of $8y^{6}+ 144y^{5}+ 640y^{4}$

Taking $8y^{4}$ common:

$\Rightarrow 8y^{4} (y^{2}+ 18y+ 80)$

Using factorization method:

$\Rightarrow 8y^{4} (y^{2}+ 10y + 8y + 80)\\\Rightarrow 8y^{4} (y (y+ 10) + 8(y + 10))\\\Rightarrow 8y^{4} (y+ 10)(y + 8))\\\Rightarrow \underline{2y^{2}} \times 4y^{2} \underline{(y+ 10)}(y + 8)) ..... (1)$

Now, Making factors of $2y^{4} + 40y^{3} + 200y^{2}$

Taking $2y^{2}$ common:

$\Rightarrow 2y^{2} (y^{2}+ 20y+ 100)$

Using factorization method:

$\Rightarrow 2y^{2} (y^{2}+ 10y+ 10y+ 100)\\\Rightarrow 2y^{2} (y (y+ 10) + 10(y + 10))\\\Rightarrow \underline {2y^{2} (y+ 10)}(y + 10) ............ (2)$

The underlined parts show the Highest Common Factor(HCF).

i.e. HCF is $2y^{2} (y+ 10)$ .

We know the relation between LCM, HCF of the two numbers 'p' , 'q' and the numbers themselves as:

$HCF \times LCM = p \times q$

Using equations (1) and (2): $\Rightarrow 2y^{2} (y+ 10) \times LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times 2y^{2} (y+ 10)(y + 10)\\\Rightarrow LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times (y + 10)\\\Rightarrow LCM = 8y^{4}(y+ 10)^{2}(y + 8)$