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vagabundo [1.1K]
3 years ago
10

I need help with this !!

Mathematics
1 answer:
Zanzabum3 years ago
7 0

Answer:

the twins will always have the same age

Step-by-step explanation:

the equation for jasmine's age is 2(3x+6), while the equation for james's age is 3(2x+4)

2(3x+6) = 2*3x + 2*6 = 6x + 12

3(2x+4) = 3*2x + 3*4 = 6x + 12

since both have the same equation, both will be the same age when you plug in the same x value

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Sin40°-sin20°/cos220°-cos200=√3​
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Answer:

1.7320508

Step-by-step explanation:

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Find gradient <br><br>xe^y + 4 ln y = x² at (1, 1)​
cricket20 [7]

xe^y+4\ln y=x^2

Differentiate both sides with respect to <em>x</em>, assuming <em>y</em> = <em>y</em>(<em>x</em>).

\dfrac{\mathrm d(xe^y+4\ln y)}{\mathrm dx}=\dfrac{\mathrm d(x^2)}{\mathrm dx}

\dfrac{\mathrm d(xe^y)}{\mathrm dx}+\dfrac{\mathrm d(4\ln y)}{\mathrm dx}=2x

\dfrac{\mathrm d(x)}{\mathrm dx}e^y+x\dfrac{\mathrm d(e^y)}{\mathrm dx}+\dfrac4y\dfrac{\mathrm dy}{\mathrm dx}=2x

e^y+xe^y\dfrac{\mathrm dy}{\mathrm dx}+\dfrac4y\dfrac{\mathrm dy}{\mathrm dx}=2x

Solve for d<em>y</em>/d<em>x</em> :

e^y+\left(xe^y+\dfrac4y\right)\dfrac{\mathrm dy}{\mathrm dx}=2x

\left(xe^y+\dfrac4y\right)\dfrac{\mathrm dy}{\mathrm dx}=2x-e^y

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2x-e^y}{xe^y+\frac4y}

If <em>y</em> ≠ 0, we can write

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2xy-ye^y}{xye^y+4}

At the point (1, 1), the derivative is

\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=1,y=1}=\boxed{\dfrac{2-e}{e+4}}

4 0
3 years ago
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Usimov [2.4K]

\huge{\boxed{\text{D}}}

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A horizontal line has a slope of 0.

A vertical line has an undefined slope.

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<em>A negative slope makes the line go downwards and to the right.</em>

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3 years ago
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Answer:

Area of ellipse is ≈ 77.78 m^{2}

Step-by-step explanation:

Given the dimension of ellipse

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  b = 5.5 m

Now, Area of ellipse = \pi ab

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Hence Area of ellipse will be 77.78 m^{2}

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