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1 answer:
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L=6+W
A=LW
sub 6+W for L
A=(6+W)(W)
expand
oh, A=50
50=W²+6W
minus 50 both sides
0=W²+6W-50
we gots to use quadratic formula
for
aW²+bW+c=0
W=
we got
a=1
b=6
c=-50
W=
W=
W=
W=
W=
W=
or W=
aprox
W=-10.6811 or W=4.68115
can't be negative width
width=4.68115 or -3√59
A=LW
sub 6+W for L
A=(6+W)(W)
expand
oh, A=50
50=W²+6W
minus 50 both sides
0=W²+6W-50
we gots to use quadratic formula
for
aW²+bW+c=0
W=
we got
a=1
b=6
c=-50
W=
W=
W=
W=
W=
W=
aprox
W=-10.6811 or W=4.68115
can't be negative width
width=4.68115 or -3√59
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Answer:
Step-by-step explanation:
hello,
i advice you check the question again if it is GF() or GF(24). i believe the question should rather be in this form;
multiplication in GF(): Compute A(x)B(x) mod P(x) =
+
+1, where A(x)=
+1, and B(x)=
.
i will solve the above question and i believe with this you will be able to solve any related problem.
A(x)B(x)=
=
=
please note that the division by the modulus above we used