Answer:
<h2><em>
2x-4</em></h2>
Step-by-step explanation:
Area of a rectangle = Length * Width
Given parameters
Area A = 8x2 – 10x – 12
Length of the rectangle = 4x+3
Required
Width of the rectangle.
Substituting the given parameters into the formula
8x2 – 10x – 12 = (4x+3)*width
width = 8x2 – 10x – 12
/4x+3
S
Factorizing the numerator
8x² – 10x – 12
= 2(4x²-5x-6)
= 2(4x²-8x+3x-6)
= 2(4x(x-2)+3(x-2))
= 2(4x+3)(x-2)
Width = 2(4x+3)(x-2)/4x+3
Width = 2(x-2)
Width = 2x-4
<em>Hence the width of the rectangle is 2x-4</em>
setup a simple algebraic equation and solve.
5x = 7x-28
-5x -5x
0=2x-28
+28 +28
28=2x
Now divide both sides by 2 and you get that she is 14
2/5 * (n - 1) < 3/5 * (n + 1)
2/5 * n - 2/5 < 3/5 * n + 3/5
- 2/5 - 3/5 < 3/5 * n - 2/5 * n
- 5/5 < 1/5 * n
- 1 < 1/5 * n /*5
- 5 < n
n > - 5
n = x
The correct result would be B) <span>x > - 5.</span>
Answer:
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Step-by-step explanation:
