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Svet_ta [14]
3 years ago
9

Multiply the following and provide the product in standard from thank you

Mathematics
1 answer:
LekaFEV [45]3 years ago
8 0

Answer:

x^3 + 4x^2 - 7x - 10

Step-by-step explanation:

To solve this we're going to use Polynomial multiplication, starting by multiplying (x-2)(x+1) = x^2 - 2x + x - 2 = x^2 - x - 2. Next, we will multiply (x^2 - x - 2)(x+ 5) = x^3 + 5x^2 -x^2 - 5x -2x -10 = x^3 + 4x^2 - 7x - 10.

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Sayyida has a circular garden of radius 21m. She ran round the garden twice. what distance did she cover?​
yawa3891 [41]

answer

C = 263.76 m

Step-by-step explanation:

C = 2×pi×r

C = 2×3.14×21

C = 131.88 m

For 2 rounds,

C = 131.88 x 2

C = 263.76 m

7 0
2 years ago
What is the solution to the system of equations below?
ANEK [815]
A. x = 7, y = 4, z = 3

How?

Just plug in the numbers.

7 + 4 + 3 = 14

11 + 3 = 14

14 = 14

Next.

4 + 3 = 7

Next.

3 = 3

5 0
2 years ago
Janelle buys 4 cases of water , each case of water contains 12 bottles, janelle drinks 3 bottles of water, what expression repre
vitfil [10]
12 times 4 minus 3 because the 12 represents how much is in each of the 4 cases and you minus that by 3 and you get your answer
8 0
3 years ago
Read 2 more answers
3) Of the 20 cookies at the bake sale, 35% are gingerbread. How many
KIM [24]

Answer:

the answer is 8. 75.

Step-by-step explanation:

25×35% = 8.75

7 0
2 years ago
Quadrilateral ABCD is inscribed in a circle. Find the measure of each of the angles of the quadrilateral. Show your work.
LuckyWell [14K]

Step-by-step explanation:

Quadrilateral ABCD is inscribed in a circle.

Opposite angles of a Quadrilateral are Supplementary.

\therefore \: \angle A + \angle C = 180° \\  \therefore \:(2x + 3) \degree+ (2x + 1) \degree = 180° \\  \therefore \: (4x + 4) \degree = 180° \\ \therefore \: (4x + 4) = 180 \\ \therefore \: 4x = 180 - 4 \\ \therefore \: 4x = 176 \\ \therefore \: x =  \frac{176}{4}  \\ \therefore \: x =  44 \\  \\  m\angle A  = (2x + 3) \degree \\  = (2 \times 44 + 3) \degree \\ = (88 + 3) \degree \\  \huge \red{ \boxed{ \therefore \: m\angle A  =91 \degree}} \\  \\ m\angle  C = (2x + 1) \degree \\  = (2 \times 44 + 1) \degree \\ = (88 + 1) \degree \\  \huge \red{ \boxed{ \therefore \: m\angle   C=89\degree}}  \\  \\ m\angle  D= (x - 10) \degree \\  = (44 - 10) \degree \\  \huge \red{ \boxed{ \therefore \: m\angle  D =34\degree}}  \\  \\ similarly \\  \\  \huge \red{ \boxed{ \therefore \: m\angle  B  = 146\degree}}   \\  \\

6 0
3 years ago
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