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3 years ago

Зc + 5 = 23 What is the answer?

Mathematics

2 answers:

34kurt3 years ago

4 0

3c + 5 = 23. Subtract 5 from each side.

3c = 18. Divide each side by 3

c = 6.

Alisiya [41]3 years ago

3 0

The answer is c = 6

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What is the product of −2/5 and −0.8? Select all that apply.

stepan [7]

Answer:

0.32

Step-by-step explanation:

You can convert -2/5 to -0.4. Then multiply them together to get 0.32. Remember that multiplying two negatives makes a positive. Hope this helps :)

7 0

2 years ago

Read 2 more answers

There is a triangle with a perimeter of 63 cm, one side of which is 21 cm. Also, one of the medians is perpendicular to one of t

NemiM [27]

Answer:

21cm; 28cm; 14cm

Step-by-step explanation:

There is no info in the problem/s text which one of the triangle's side is 21 cm. That is why we have to try all possible variants.

Let the triangle is ABC . Let the AK is the angle A bisector and BM is median.

Let O is AK and BM cross point.

Have a look to triangle ABM. AO is the bisector and AOB=AOM=90 degrees (means that AO is as bisector as altitude)

=> triangle ABM is isosceles => AB=AM (1)

1. Let AC=21 So AM=21/2=10.5 cm

So AB=10.5 cm as well. So BC= P-AB-AC=63-21-10.5=31.5 cm

Such triangle doesn' t exist ( is impossible), because the triangle's inequality doesn't fulfill. AB+AC>BC ( We have 21+10.5=31.5 => AB+AC=BC)

2. Let AB=21 So AM=21 and AC=42 .So BC= P-AB-AC=63-21-42=0 cm- such triangle doesn't exist.

3. Finally let BC=21 cm. So AB+AC= 63-21=42 cm

We know (1) that AB=AM so AC=2*AB. So AB+AC=AB+2*AB=3*AB

=>3*AB=42=> AB=14 cm => AC=2*14=28 cm.

Let check if this triangle exists ( if the triangle's inequality fulfills).

BC+AB>AC 21+14>28 - correct=> the triangle with the sides' length 21cm,14 cm, 28cm exists.

This variant is the only possible solution of the given problem.

6 0

3 years ago

I need help lol. Find the lateral surface area of the figure to the nearest tenth.

Mekhanik [1.2K]

Answer:

101.9 sq ft

Step-by-step explanation:

The figure is missing: find it in attachment.

Here we want to find the lateral surface area of the figure, which is the sum of the areas of all faces.

We have in total 5 faces:

- 1 of them is rectangle with sizes (8.5 ft x 3.3 ft), so its area is

$A_1=8.5 \cdot 3.3 =28.1 ft^2$

- 1 of them is a rectangle with sizes (3.3 ft x 5.1 ft), so its area is

$A_2 = 3.3\cdot 5.1 =16.8 ft^2$

- 1 of them is a rectangle with sizes (6.8 ft x 3.3 ft), so its area is

$A_3 = 6.8\cdot 3.3 =22.4 ft^2$

- Finally, we have 2 triangular faces (top and bottom), so their area is

$A_T=\frac{1}{2}bh$

where

b = 5.1 ft is the base

h = 6.8 ft is the height (because the triangle is a right triangle)

So the area of the triangle is

$A_T=\frac{1}{2}(5.1)(6.8)=17.3 ft^2$

So the total lateral surface area of the figure is:

$A=A_1+A_2+A_3+2A_T=28.1+16.8+22.4+2(17.3)=101.9 ft^2$

5 0

3 years ago

a gardener has 322 tulip bulbs she wants to plant rows of 15 bulbs how many bulbs can be planted how many bulbs will she have le

Elden [556K]

Answer:315 bulbs planted and 7 left over

Step-by-step explanation:322/15 = 21.44

Roughly around 21 rows.

21 x 15 = 315 bulbs planted

322 - 315 = 7 bulbs left over

3 0

3 years ago

Helppppppppppppppppp asappppppp

Pani-rosa [81]

Answer:

140

Step-by-step explanation:

<u>As per picture:</u>

∠PTQ and ∠RTS are vertical angles and they are equal

∠PTQ = (x + 28)°
∠RTS = (2x + 16)°
∠PTQ = ∠RTS
x + 28 = 2x + 16
2x - x = 28 - 16
x = 12

∠PTR is supplementary with ∠PTQ and their sum is 180°

∠PTQ = 12 + 28 = 40°
∠PTR = 180 - 40 = 140°

6 0

3 years ago