Answer:
(6 3/4) * (-11.5) = -6218 = -7758 = -77.625
Given
x=0 and x =10 and x1, x2, x3, x4 are the midpoints of five equal intervals
Answer
The 5 equal intervals are 2 , 4 , 6, 8 10
Mid points are 1, 3 , 5 , 7 , 9
Option B is correct
Answer:
The random variable (number of toppings ordered on a large pizza) has a mean of 1.14 and a standard deviation of 1.04.
Step-by-step explanation:
<em>The question is incomplete:</em>
<em>The probability distribution is:</em>
<em>x P(x)
</em>
<em>
0 0.30
</em>
<em>1 0.40
</em>
<em>2 0.20
</em>
<em>3 0.06
</em>
<em>4 0.04</em>
The mean can be calculated as:
![M=\sum p_iX_i=0.3\cdot 0+0.4\cdot 1+0.2\cdot 2+0.06\cdot 3+0.04\cdot 4\\\\M=0+0.4+0.4+0.18+0.16\\\\M=1.14](https://tex.z-dn.net/?f=M%3D%5Csum%20p_iX_i%3D0.3%5Ccdot%200%2B0.4%5Ccdot%201%2B0.2%5Ccdot%202%2B0.06%5Ccdot%203%2B0.04%5Ccdot%204%5C%5C%5C%5CM%3D0%2B0.4%2B0.4%2B0.18%2B0.16%5C%5C%5C%5CM%3D1.14)
(pi is the probability of each class, Xi is the number of topping in each class)
The standard deviation is calculated as:
![s=\sqrt{\sum p_i(X_i-M)^2}\\\\s=\sqrt{0.3(0-1.14)^2+0.4(1-1.14)^2+0.2(2-1.14)^2+0.06(3-1.14)^2+0.04(4-1.14)^2}\\\\s=\sqrt{0.3(-1.14)^2+0.4(-0.14)^2+0.2(0.86)^2+0.06(1.86)^2+0.04(2.86)^2}\\\\ s=\sqrt{0.3(1.2996)+0.4(0.0196)+0.2(0.7396)+0.06(3.4596)+0.04(8.1796)}\\\\s=\sqrt{0.3899+0.0078+0.1479+0.2076+0.3272}\\\\ s=\sqrt{ 1.0804 }\\\\s\approx 1.04](https://tex.z-dn.net/?f=s%3D%5Csqrt%7B%5Csum%20p_i%28X_i-M%29%5E2%7D%5C%5C%5C%5Cs%3D%5Csqrt%7B0.3%280-1.14%29%5E2%2B0.4%281-1.14%29%5E2%2B0.2%282-1.14%29%5E2%2B0.06%283-1.14%29%5E2%2B0.04%284-1.14%29%5E2%7D%5C%5C%5C%5Cs%3D%5Csqrt%7B0.3%28-1.14%29%5E2%2B0.4%28-0.14%29%5E2%2B0.2%280.86%29%5E2%2B0.06%281.86%29%5E2%2B0.04%282.86%29%5E2%7D%5C%5C%5C%5C%20s%3D%5Csqrt%7B0.3%281.2996%29%2B0.4%280.0196%29%2B0.2%280.7396%29%2B0.06%283.4596%29%2B0.04%288.1796%29%7D%5C%5C%5C%5Cs%3D%5Csqrt%7B0.3899%2B0.0078%2B0.1479%2B0.2076%2B0.3272%7D%5C%5C%5C%5C%20s%3D%5Csqrt%7B%201.0804%20%7D%5C%5C%5C%5Cs%5Capprox%201.04)
X^2 = 16/9
X = 4/3
Length of X is 1 1/3 inches