Question

Find the point slope form of the equation of the line passing through the points (-6,-4) and (2,-5)

Answer 1

$y+4=-\frac{1}{8} \times(x+6)$ or $y+5=-\frac{1}{8} \times(x-2)$ is the slope point form of the line.

Step-by-step explanation:

The given points are (-6,-4) and (2,-5)  are as $\left(x_{1}, y_{1}\right) \text { and }\left(x_{2}, y_{2}\right)$. Need to find out the point slope form of the line which passes through these points. The formula of slope point form for an equation of a straight line as

                $\left(y-y_{1}\right)=\text { slope } \times\left(x-x_{1}\right)$

Hence, we have two points and we have to find out first slope of the line

             $\left(y-y_{1}\right)=m \times\left(x-x_{1}\right)$

Where m is the slope and $\left(x_{1}, y_{1}\right)$ is a point the line passes through.  Hence, we have two points and we have to find out first slope of the line

           $\text {slope}=\frac{-5-(-4)}{2-(-6)}=-\frac{1}{8}$

Now, slope point form of the line is,

                $y-(-4)=-\frac{1}{8} \times(x-(-6))$

               $y+4=-\frac{1}{8} \times(x+6)$

Similarly at (2,5),

              $y-(-5)=-\frac{1}{8} \times(x-2)$

              $y+5=-\frac{1}{8} \times(x-2)$