The vertex of the quadratic equation is (-5, - 28). In vertex form, y = a(x - h)2<span> + </span><span>k, (h, k) is the vertex of the equation.</span>
Answer:
2
Step-by-step explanation:
f(x)=2x^2+9x-5
When we are find how many times it intersects the x axis, we are finding the zero's. Set the equation equal to zero
0=2x^2+9x-5
Factor the equation
0 = (2x+1) (x-5)
2*1
1*-5 = -5
2*-5 +1*1 = -9
This checks for the first last and middle terms so we factored correctly
Then using the zero product property
2x+1 = 0 and x-5 =0
2x = -1 x=5
x = -1/2 and x=5
This function crosses the x axis 2 times
Answer:
<em>x - y = 2</em>
Step-by-step explanation:
First of all, you would combine like terms, giving you 4x - 4y + 1 = 9.
Next, subtract the numbers, which gives you 4x - 4y = 8.
Finally, divide both sides by 4, which will come to the conclusion of x - y = 2, the simplest form of which this equation can be broken down to.
There are 430 non square numbers that lie between 
and 
.
Given two numbers and and we are require to find non square numbers that lie between them.
Numbers can be consecutive numbers or non consecutive numbers. In our question we will find the consecutive numbers.
Square numbers are those numbers whos square is in a proper number means decimal should not be there.
First number=
Second number=
First we have to find the exact value of numbers by finding the square of these numbers.
First number=215*215=46225
Second number=216*216=46656
Numbers that lie between them=(46656-46225)-1
=431-1
=430
Hence 430 numbers lie between and .
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