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3 years ago

9.2 Find the

Mathematics

1 answer:

Blababa [14]3 years ago

8 0

Answer:

Poorly formated. Please fix the question so it is more understandable!

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A rectangle has an area of 112 m2. The length is 12 m more than four times the width. What is the length of a diagonal of the re

tankabanditka [31]

The answer is 1,344 hope this helps

3 0

4 years ago

Look at the attachment below :)<br><br> Thanks for those who help!

kiruha [24]

The perimeters of the figures are the same.

For the rectangle:

P = 2(8) + 2(2)
P = 16 + 4
P = 20

For the square:

P = 5(4) *4 represents the four sides of the square.
P = 20

Hope that helps!

3 0

3 years ago

Read 2 more answers

Let lim x→a g(x) = 1 , lim x→a f(x) = 0, lim x→a h(x) = 7. Find following limits if they exist. If not, enter DNE (’does not exi

posledela

Answer:

Using the properties of the limits, we have that:

1. $lim_{x\rightarrow a}(g(x)+f(x))=lim_{x\rightarrow a}g(x)+lim_{x\rightarrow a}f(x)=1+0=1$

2. $lim_{x\rightarrow a}(g(x)-f(x))=lim_{x\rightarrow a}g(x)-lim_{x\rightarrow a}f(x)=1-0=1$

3. $lim_{x\rightarrow a}(g(x)*h(x))=lim_{x\rightarrow a}g(x)*lim_{x\rightarrow a}h(x)=1*7=7$

4. $lim_{x\rightarrow a}(g(x)*f(x))=lim_{x\rightarrow a}g(x)*lim_{x\rightarrow a}f(x)=1*0=0$

5. $lim_{x\rightarrow a}(\frac{g(x)}{h(x)})=\frac{lim_{x\rightarrow a}g(x)}{lim_{x\rightarrow a}h(x)}=\frac{1}{7}$

6. $lim_{x\rightarrow a}(\frac{h(x)}{g(x)})=\frac{lim_{x\rightarrow a}h(x)}{lim_{x\rightarrow a}g(x)}=\frac{7}{1}=7$

7. $lim_{x\rightarrow a} pf(x)=plim_{x\rightarrow a}f(x)=p*0=0$

8. $lim_{x\rightarrow a}f(x)-1=lim_{x\rightarrow a}f(x)-lim_{x\rightarrow a}1=0-1=-1$

9. $lim_{x\rightarrow a}\frac{1}{f(x)-h(x)}=\frac{lim_{x\rightarrow a}1}{lim_{x\rightarrow a}f(x)-h(x)}=\frac{1}{lim_{x\rightarrow a}f(x)-lim_{x\rightarrow a}h(x)}=\frac{1}{0-7}=-\frac{1}{7}$

6 0

3 years ago

The volume v in cubic feet of a shipping box is modeled by the polynomial function V(x)=x^3-2x^2-19x+20, where X is the length o

Serhud [2]

Answer:

Step-by-step explanation:

The volume v in cubic feet of a shipping box is modeled by the polynomial function V(x)=x^3-2x^2-19x+20, where X is the length of the box. To determine if x = - 2 is not a zero of the polynomial function, we would substitute x = - 2 into the polynomial function, V(x)=x^3-2x^2-19x+20. If the result is not zero, it means that x = - 2 not a zero of the polynomial function. Therefore

(-2)^3-2(-2)^2-19(-2)+20

= - 8 - 8 + 38 + 20 = 42

Since 42 is not equal to 0, then x = - 2 not a zero of the polynomial function.

4 0

3 years ago

The expression (x8 - 48) can be factored as (x2 - 42)2 (x2 + 42)2. <br> a. True<br> b. False

kupik [55]

I think the answer is false, but I'm not sure. I wish I could help more ):

8 0

4 years ago