Answer:
4 and 3 <------- That's the set I believe!
Answer:
The worth of the car after 6 years is £2,134.82
Step-by-step explanation:
The amount at which Dan buys the car, PV = £2200
The rate at which the car depreciates, r = -0.5%
The car's worth, 'FV', in 6 years is given as follows;
Where;
r = The depreciation rate (negative) = -0.5%
FV = The future value of the asset
PV = The present value pf the asset = £2200
n = The number of years (depreciating) = 6
By plugging in the values, we get;
The amount the car will be worth which is its future value, FV after 6 years is FV ≈ £2,134.82 (after rounding to the nearest penny (hundredth))
Answer: $129
Step-by-step explanation: First, you round 2.75 up to 3 and then you multiply by 43. Boom, $129.
Answer:
45% increase
Step-by-step explanation:
The new number (87) is bigger than the original number (60), so this is a percent increase.
To find the percent of change, which in this case is a percent increase, take the change amount and divide by the original, then convert to a percent.
Subtract to find the change.
87 - 60 is 27.
27 is the amount of change.
change/original
= 27/60
= .45
Times by 100 to change to a percent.
.45 × 100
= 45%
Answer:
100 Joules
Step-by-step explanation:
We use the definition of Work as the force applied multiplied by the distance the object was moved. In our case the force exerted is 50 N, over a distance of 2 meters, therefore:
Work = F * d = 50 N * 2 m = 100 N*m = 100 Joules
The SI unit for Newton times meter is called "Joule".