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alina1380 [7]
2 years ago
9

Convert 32 km to decimetres fill in the blanks. Please show your work and show where it goes.

Mathematics
1 answer:
PtichkaEL [24]2 years ago
5 0

Answer:

320,000 dm

Step-by-step explanation:

A decimetre is equivalent to 10 cm or \frac{1}{10}m. We can use this to work out the answer.

1km is equal to 1,000m or 10,000dm (using the second option above).

This means for 32km, it should be 32×10,000dm.

This gives 320,000 dm.

I'm unsure of where you need to fill in on the worksheet, but this should help.

**This content involves converting measurement units, which oyu may wish to revise. I'm always happy to help!

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The scale factor, or linear scale factor, is the ratio of two corresponding side lengths of similar figures.

Step-by-step explanation:

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3 years ago
What is the LCM of 8 and 10
iragen [17]
40


8x5=40
10x4=40

Hope this helps
3 0
2 years ago
All the boxes in a certain warehouse were arranged in stacks of 12 boxes each, with no boxes left over. After 60 additional boxe
AveGali [126]

Answer:

(1) There were fewer than 110 boxes in the warehouse before the 60 additional boxes arrived. (2) There were fewer than 120 boxes in the warehouse after the 60 additional boxes arrived.

Step-by-step explanation:

Given that all the boxes in a certain warehouse were arranged in stacks of 12 boxes each, with no boxes left over.

This implies that boxes are in multiples of 12

i.e. 12, or 24, or 36 or....

Let us say this as 12m for m an integer

Now additional boxes arrived =60

Total number of boxes now = 12m+60

This when arranged in stacks of 14,nothing left out

Or this is multiple of 14

12m+60 = 14n for some positive integer n.

By trial and error we find that if 60 is to be divided by 14, 24 should be added and 24 is a multiple of 12.

So we say originally 24 boxes were there now 84 boxes there.

Hence both options are right.

(1) There were fewer than 110 boxes in the warehouse before the 60 additional boxes arrived. (2) There were fewer than 120 boxes in the warehouse after the 60 additional boxes arrived.

3 0
3 years ago
) Evaluating a polynomial limit analytically You should have learned by now the process for finding the derivative of a polynomi
wolverine [178]

Answer:

This code or is program to find a given value of derivative of  a polynomial.

Step-by-step explanation:

We know already how to apply or make the procedures mathematically talking so this short program will eventually help you how to find logic.

// libraries

#include <stdio.h>

#include <conio.h>

//use to control floating elements

float poly(float a[], int, float);

//main

int main()

{

// Enter the degree of polynomial equation

float x, a[10], y1;

int deg, i;

printf("Enter the degree of polynomial equation: ");

scanf("%d", &deg);

printf("Ehter the value of x for which the equation is to be evaluated: ");

// Enter the coefficient of x to the power

scanf("%f", &x);

for(i=0; i<=deg; i++)

{

 printf("Enter the coefficient of x to the power %d: ",i);

 scanf("%f",&a[i]);

}

// The value of polynomial equation for the value of x

y1 = poly(a, deg, x);

 

printf("The value of polynomial equation for the value of x = %.2f is: %.2f",x,y1);

 

return 0;

}

/* function for finding the value of polynomial at some value of x */

float poly(float a[], int deg, float x)

{

float p;

int i;

 

p = a[deg];

 

for(i=deg;i>=1;i--)

{

 p = (a[i-1] + x*p);

}

 

return p;

}

8 0
3 years ago
Ty in advance for whoever does this. Find the range and put it on the graph. thank you &lt;3
ser-zykov [4K]

Answer:

Step-by-step explanation:

y_{1} = - 4 - 2( - 3) = 2

y_{2} = - 4 - 2( - 2) = 0

y_{3} = - 4 - 2( - 1) = - 2

y_{4} = - 4 - 2( 0 ) = - 4

y_{5} = - 4 - 2( 1 ) = - 6

Range: { 2, 0, - 2, - 4, - 6 }

8 0
3 years ago
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