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ZanzabumX [31]
3 years ago
12

Using a table to graph equations in standard form help.Be dumb i will report ​

Mathematics
1 answer:
sertanlavr [38]3 years ago
8 0

Answer:

X, Process, Y

-2, y = -2 - 3, -5

-1, y = -1 - 3, -4

0, y = 0 - 3, -3

1, y = 1 - 3, -2

2, y = 2 - 3, -1

X = -2, -1, 0, 1, 2

Y = -5, -4, -3, -2, -1

Step-by-step explanation:

Coordinates to the graph are (-2,-5) (-1,-4) (0,-3) (1,-2) (2,-1)

Graph is the image below.

you want to get Y by itself so here is how you do that.

-x+y=-3\\+x       +x\\

Now we have y=x-3

now we plug x into the equation to get our answer.

-2 - 3 = -5

-1 - 3 = -4

0 - 3 = -3

1 - 3 = -2

2 - 3 = -1

Hope this helps!

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The numbers of teams remaining in each round of a single-elimination tennis tournament represent a geometric sequence where an i
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Answer:

a_n = 128\bigg(\dfrac{1}{2}\bigg)^{n-1}

Step-by-step explanation:

We are given the following in the question:

The numbers of teams remaining in each round follows a geometric sequence.

Let a be the first the of the geometric sequence and r be the common ration.

The n^{th} term of geometric sequence is given by:

a_n = ar^{n-1}

a_4 = 16 = ar^3\\a_6 = 4 = ar^5

Dividing the two equations, we get,

\dfrac{16}{4} = \dfrac{ar^3}{ar^5}\\\\4}=\dfrac{1}{r^2}\\\\\Rightarrow r^2 = \dfrac{1}{4}\\\Rightarrow r = \dfrac{1}{2}

the first term can be calculated as:

16=a(\dfrac{1}{2})^3\\\\a = 16\times 6\\a = 128

Thus, the required geometric sequence is

a_n = 128\bigg(\dfrac{1}{2}\bigg)^{n-1}

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3 years ago
Twelve students have equally likely chance of being selected in a drawing at school. Eight are girls and four are boys. What is
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There are 4 boys and 12 students in total. It would be 4/12, but if it was to be simplified, it would be 1/3. The probability of a boy being selected is 1/3.
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Answer:

A

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