An=a1+d (n-1)
a1= 7
find d
Let's use a2
a2=1
1=7+d (2-1)
1=7+d
-7 both sides
d=-6
explicit formula is
an=7+-6 (n-1)
a14=?
a14=7-6 (14-1)
a14=7-6×13
a14=7-78
a14=-71
Answer:
3.1
Step-by-step explanation:
3 1/2=3.5
2/5=0.4
3.5-0.4=3.1
Answer:
Below is the solution to the given points:
Step-by-step explanation:
For point a:
There have 30 overviews paired here and we'd like to analyze the mean studying time in the middle and final periods. It will employ a paired t-test. The difference (d) = mid - final
Hypotheses:

For point b:
More than three variables should be examined here because ANOVA is employed in one method.
For point c:
This one Z test is used since we have the standard difference in population.
Hypotheses:
For point d:
Since not knowing the sample standard deviation, we will use an individual sample t-test.
Hypotheses:
Answer:
0.65
Step-by-step explanation: Please brainliest!
Answer:
Type I error is : to conclude that the current mean hours per week is higher than 4.5, when in fact, it is the same.
Step-by-step explanation:
We are given that an organization reported that teenagers spent 4.5 hours per week, on average, on the phone. The organization thinks that, currently, the mean is higher. For this fifteen randomly chosen teenagers were asked how many hours per week they spend on the phone. The sample mean was 4.75 hours with a sample standard deviation of 2.0 hours.
Let Null Hypothesis,
:
4.5 hours {means that the current mean hours per week is less than or equal to 4.5}
Alternate Hypothesis,
:
> 4.5 hours {means that the current mean hours per week is higher than 4.5}
<em>Now, T</em><u><em>ype I error states that</em></u><em> : Probability of rejecting null hypothesis given the fact that it was true or Rejecting the true null hypothesis.</em>
<u>So, according our question;</u>
Type I error is to conclude that the current mean hours per week is higher than 4.5, when in fact, it is the same.