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3 years ago

The diagram shows a right-angled triangle.

Mathematics

1 answer:

Alexus [3.1K]3 years ago

8 0

Step-by-step explanation:

there is no diagram so I'm just going to guess this however

sin x = 6/9

sin x = 2/3

sin x = 0.67

x = sin inverse of 0.67

x = 42.1

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If 4x-4t=-10 is a true equation, what would be the value of 4x-4y+9?

Andre45 [30]

Answer:

uhh... that is impossible to know since we don't know the value 'y'

Step-by-step explanation:

4 0

3 years ago

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2x - (3x + 6) Please help me with this equation guys!!!

katen-ka-za [31]

1. 2x - (3x + 6).....negative before parentheses makes everything inside parentheses opposite
2. 2x - 3x - 6....2x - 3x = -1x
3. -1x - 6

Answer:
-1x - 6

4 0

3 years ago

the intake pipe can fill a certain tank in 6 hours when the outlet pipe is closed, but with the outlet pipe open it takes 9 hour

Leona [35]

The outlet pipe will take 18 hours to empty the tank.

St<u>ep-by-step explanation:</u>

Number of hours taken by inlet pipe to fill the tank=6

work done by the inlet pipe in 1 hour=1/6

Number of hours taken by the inlet pipe to fill the tank with the outlet pipe open=9

work done by the inlet pipe in 1 hour with outlet pipe open=1/9

we have to determine the time taken by the outlet pipe to empty the tank

The inlet and outlet pipe does the opposite work.

$\\time\ taken\ by\ the\ outlet\ pipe\ to\ empty\ the\ tank=x\\work\ done\ by\ the\ outlet\ pipe\ in\ 1\ hour=1/x\\(1/6-1/x)9=1\\1/6-1/x=1/9\\1/x=1/6-1/9=3/54\\x=54/3=18$

The outlet pipe takes 18 hours to empty the tank.

6 0

3 years ago

Find the center,vertices,foci,and asymptotes of the hyperbola.

bogdanovich [222]

Answer:

The center is (8 , -9)

The vertices are (11 , -9) and (5 , -9)

The foci are (8 , -9 + √58) and (8 , -9 - √58)

The equations of the asymptotes are y = 3/7(x − 8) - 9 , y = -3/7 (x − 8) - 9

Step-by-step explanation:

- The standard form of the equation of a hyperbola with

center (h , k) and transverse axis parallel to the y-axis is

(y - k)²/a² - (x - h)²/b² = 1

- The length of the transverse axis is 2 a

- The coordinates of the vertices are ( h ± a , k )

- The length of the conjugate axis is 2 b

- The coordinates of the co-vertices are ( h , k ± b )

- The coordinates of the foci are (h , k ± c), where c² = a² + b²

- The equations of the asymptotes are y = ± a/b (x − h) + k

* Now lets solve the problem

∵ (y + 9)²/9 - (x - 8)²/49 = 1

∴ h = 8 and k = -9

∴ a² = 9 ⇒ a = ± 3

∴ b² = 49 ⇒ b = ± 7

∵ c² = a² + b²

∴ c² = 9 + 49 = 58

∴ c = ± √58

∵ The center is (h , k)

∴ The center is (8 , -9)

∵ The coordinates of the vertices are ( h ± a , k )

∴ The vertices are (8 + 3 , -9) and (8 - 3 , -9)

∴ The vertices are (11 , -9) and (5 , -9)

∵ The coordinates of the foci are (h , k ± c)

∴ The foci are (8 , -9 + √58) and (8 , -9 - √58)

∵ The equations of the asymptotes are y = ± a/b (x − h) + k

∴ The equations of the asymptotes are y = 3/7 (x - 8) - 9 and

y = -3/7 (x − 8) - 9

7 0

3 years ago

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Ben drinks tea at an incredible rate. He drinks 3\dfrac123 2 1 3, start fraction, 1, divided by, 2, end fraction liters of tea

barxatty [35]

Answer:

Restating the question clearly:

Ben drinks tea at an incredible rate. He drinks 3 1/2 liters of tea every 2/3 of an hour. How much does he drink in one hour?

Answer:

He drinks $5\frac{1}{4}\ liters\$ in 1 hour

Step-by-step explanation:

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5 0

3 years ago