Answer:
2934.5
Step-by-step explanation:
2934.46692 Rounded to 1 Sig Fig is 2934.5
Answer:
1. distance = sqrt( (7-7)^2+(2- -8)^2) = 10
2. check out desk (0,0 ) => distance = sqrt( (0- -9)^2+(0-0)^2) = 9
3. last corner ( -3, 4)
4. area = sqrt( (-10- -10)^2+(10-4)^2) x sqrt( (-3- -10)^2+(10-10)^2) = 6x7 =42
5. check desk (0,0), south direction = negative y axis => P_beginning (0,-20), P_end (0,-(20+25)) = (0,-45)
6. A(-2,-1) and B(4,-1) lie in y =-1. AB = sqrt( (-2- 4)^2+(-1- -1)^2) =6
=> area = 3.6x6 =21.6
=> peri = 2x(3.6+6) = 19.2
7. A(-5,4) and B(2,4), AB = sqrt( (-5- 2)^2+(4- -4)^2) = 7 => AB is base
=> p = peri = 7+ 8.3x2 = 23.6
=> area = sqrt[px(p-7)x(p-8.3)x(p-8.3)]
=sqrt[23.6x(23.6-7)x(23.6-8.3)x(23.6-8.3)] = 302.8
The domain is the origin of the arrow
domain = {-2,2,3,4}
Option d is the answer
If there is 2 field trips with 23 students and each student costs $5 dollars. So for the 1st trip it will be 23x$5
1st trip- $115
And on the second trip its the same because there is 23 students that cost 5 dollars so it will be 23x5
2nd trip- $115
To find out the total of both trips youd add 115+115/
In total, for both trips it will cost $230 dollars.
Answer:
Probability that a car need to be repaired once = 20% = 0.20
Probability that a car need to be repaired twice = 8% = 0.08
Probability that a car need to be repaired three or more = 2% = 0.02
a) If you own two cars what is the probability that neither will need repair?
Probability that a car need to be repaired once , twice and thrice or more= 0.20+0.08+0.02=0.3
Probability that car need no repair = 1-0.3=0.7
Neither car will need repair=
b) both will need repair?
Probability both will need repair = 
c)at least one car will need repair
Neither car will need repair=
Probability that at least one car will need repair= 1-0.49 = 0.51
