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sineoko [7]
3 years ago
11

Evaluate 3x – 4 when x=7. The value of the expression is​

Mathematics
2 answers:
amid [387]3 years ago
6 0

Answer:

Let's solve your equation step-by-step.

3x+2=14

Step 1: Subtract 2 from both sides.

3x+2−2=14−2

3x=12

Step 2: Divide both sides by 3.

3x /3 = 12/3

<u>x=4</u>

Novay_Z [31]3 years ago
4 0

Answer:

17

Step-by-step explanation:

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3 0
3 years ago
Use a graphing utility to graph the function and visually estimate the limits.
levacccp [35]

The value of the \lim_{x \to 0} f(x) and \lim_{x \to \frac{\pi }{3} } f(x) are 0 and 1.153 .

<h3></h3><h3>What is the limiting value of a function?</h3>

Limiting Value of a Function. The function's limit is the value of the function as its independent variable, such as x approaches a certain value called the limiting value. For simple equations, this is similar to finding out the value of y when x has a unique value.

Given that,

f(x) = 4x cos x

First to calculate the limit value of the given function at x=0.

\lim_{x \to 0} f(x) = \lim_{x \to 0} 4x cosx

                   = 4×0×1                              (∵ cos0 = 1)

\lim_{x \to 0} f(x) = 0

Similarly,

\lim_{x \to \frac{\pi }{3} } f(x) = \lim_{x \to \frac{\pi }{3} } 4x cosx

                     =  4×\frac{\pi }{3}×cos\frac{\pi }{3}

                     =  4×\frac{\pi }{3}×\frac{1}{2}                          (∵cos60° = \frac{1}{2})

\lim_{x \to \frac{\pi }{3} } f(x)  = 1.153

Hence, The value of the \lim_{x \to 0} f(x) and \lim_{x \to \frac{\pi }{3} } f(x) are 0 and 1.153.

To learn more about the limit of the function from the given link:

brainly.com/question/23935467

#SPJ9

8 0
1 year ago
9/16 divided by 9 plz help thx for everyone that has helped me
Verizon [17]
0.5625 will be the answer to 9 divided by 16
3 0
2 years ago
36.00x0.07 show explanation
makkiz [27]

Answer: 2.52

Step-by-step explanation: 36.00x0.07

36.00 is the same as 36

so, 36x0.07=2.52

5 0
2 years ago
A country's population in 1994 was 182 million. In 2002 it was 186 million. Estimate the population in 2004 using the exponentia
iogann1982 [59]
\bf =ae^{kt}\qquad &#10;\begin{cases}&#10;1994\impliedby \textit{year 0, starting point}\\&#10;t=0\qquad P=182&#10;\end{cases}\implies 182=ae^{k0}&#10;\\\\\\&#10;182=a\cdot e^0\implies 182=a\cdot 1\implies 182=a&#10;\\\\\\&#10;thus\qquad P=182e^{kt}\\\\&#10;-------------------------------\\\\

\bf P=182e^{kt}\qquad &#10;\begin{cases}&#10;2002\impliedby \textit{8 years later}\\&#10;t=8\qquad P=186&#10;\end{cases}\implies 186=182e^{k8}&#10;\\\\\\&#10;\cfrac{186}{182}=e^{8k}\implies ln\left( \frac{93}{91} \right)=ln(e^{8k})\implies ln\left( \frac{93}{91} \right)=8k&#10;\\\\\\&#10;\cfrac{ln\left( \frac{93}{91} \right)}{8}=k\implies 0.0027\approx k\implies \boxed{P=182e^{0.0027t}}

what's the population in 2004?  well,  from 1994 to 2004 is 10 years later, so t = 10

plug that in, to get P for 2004
3 0
3 years ago
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