Answer:
theta =
+ 2
n,
+ 2
n,
+ 2
n,
+ 2
n
Step-by-step explanation:
sin^2 theta - cos^3 theta = 1
cos^3 theta = 1 - sin^2 theta
sin^2 theta - cos^3 theta = 0
Substitute
sin^2 theta - ( 1 - sin^2 theta ) = 0
Distribute negative
sin^2 theta - 1 + sin^2 theta = 0
Combine same values
2sin^2 theta - 1 = 0
2sin^2 theta = 1
sin^2 theta = ![\frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D)
sin theta = +- ![\frac{1}{\sqrt{2}}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Csqrt%7B2%7D%7D)
Right Triangle: 1 - 1 - ![\sqrt{2}](https://tex.z-dn.net/?f=%5Csqrt%7B2%7D)
theta =
+ 2
n,
+ 2
n,
+ 2
n,
+ 2
n
period of Sin function is 2![\pi](https://tex.z-dn.net/?f=%5Cpi)