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Delvig [45]
3 years ago
11

⚠️6TH GRADE MATH PLEASE HELP I WILL MARK CROWN⚠️

Mathematics
1 answer:
zaharov [31]3 years ago
4 0

Answer:

0.40d

d - 0.60d

Step-by-step explanation:

d - 0.60

This doesn't work because it wants 60<em><u>%</u></em> 0.60 without the percent is a decimal number, and is not 60% of d.

100% - 60% = 40%

0.40d works because it is multiplying 0.40 and d which is also 40%.

d - 0.60d works because it is multiplying 0.60 and d which is also 60% and then subtract it from d.

0.60d doesn't work because it want the discounted price not the discount.

1 - 0.60d doesn't work because we don't know that d = 1, so it is subtracting the discount from 1 not d.

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An open box is to be constructed so that the length of the base is 3 times larger than the width of the base. If the cost to con
natta225 [31]

Answer:

Step-by-step explanation:

Let assume that the volume = 88 cubic feet

Then:

L = 3w --- (1)volume = l \times w \times h \\ \\ 88 =  (3w)   \times w  \times h \\ \\ 3w^2 h= 88 \\ \\ h = \dfrac{88}{3w^2}--- (2) \\ \\

The construction cost now is:

C = 4(l \times w) + 2 ( w  \times h) + 2(l \times h) \\ \\ C = 4(3w^2) + 2(w  \times \dfrac{88}{3w^2}) + 2(3w \times \dfrac{88}{3w^2}) \\\\ C = 12w^2 + \dfrac{176}{3w} + \dfrac{176}{w}

Now, to determine the minimum cost:

\dfrac{dC}{dw}= 0  \\ \\ \implies 24 w - \dfrac{176}{3w^2}- \dfrac{176}{w^2}=0 \\ \\ 24 w ^3 = \dfrac{176}{w^2}(\dfrac{1}{3}+1) \\ \\ 24 w ^3 = \dfrac{176(4)}{3} \\ \\ w^3 = \dfrac{88}{3(3)}

w = \dfrac{88}{3(3)}^{1/3} \ feet

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length = 3 ( \dfrac{88}{3(3)})^{1/3} \ feet

height = ( 88})^{1/3} (3)^{1/3} \ feet

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