Answer:
Jacqueline runs at 6.25 minutes per mile
Step-by-step explanation:
Here we have that the total training time for Jacqueline = 54 minutes
The time for which Jacqueline swims = 30 minutes
Therefore, the time in which Jacqueline runs = 54 min. - 30 min. = 20 minutes
Therefore the equation for Jacqueline's speed = Distance/Time we have
Jacqueline's pace = 3.2 miles/20 minutes = 0.16 miles/minute
Therefore Jacqueline's pace = 0.16 miles/minute
The equation for Jacqueline's pace in miles/minute is presented as follows
Jacqueline's pace in miles/minute = Time of running/Distance
Jacqueline's pace in miles/minute = 1/0.16 miles/minute = 6.25 minutes/mile.
(y2-y1)/(x2-x1) (-3 - (-8))/(6- (-5))= 5/11
-2m-9 is the simplified expression
Setting up a right triangle, the 100 would be the hypotenuse, the 45 would be the angle of elevation, and you're looking for the opposite side.
Sin 45 = x/100
100sin45 = x
100 * ✓(2)/2 = x
50 ✓2 =x
x = 50✓2 ft
