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Novosadov [1.4K]
4 years ago
7

What is the distance between point R (−1, 7) and point T (−7, 7) ?

Mathematics
1 answer:
Slav-nsk [51]4 years ago
8 0

Answer:

Step-by-step explanation:

distance = √(x₂-x₁)² + (y₂-y₁)²

= √(-1 - [-7] )² + (7  -7)²   =√(-1 +7  )² +0

= √ (6)² = 6 units

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Sandra's bird feeder holds 3/5 of a cup of birdseed. Sandra is filling the bird feeder with a scoop that holds 1/10 of a cup. Ho
Alexeev081 [22]
6, because 3/5=6/10 and 1/10*6=6/10.
8 0
3 years ago
What will the range values be for the function f(g) = 3g - 5 for the domain {-1.5, 2, 4}?
DochEvi [55]
3(-1.5)-5=
-4.5-5=
-9.5

3(2)-5=
6-5=
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3(4)-5=
12-5=
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{f(-1.5),f(2),f(4)} = {-9.5,1,7} 
5 0
3 years ago
Write an equation with more than three steps where x=3.5
Serhud [2]


Try this:

2(x+5)=17

By distributing 2 to x and five you're left with 2x+10=17

Subtract 10 from both sides to equal 2x=7

Divide 7 for x=3.5

6 0
3 years ago
What is the solution to the inequality below?
dimaraw [331]
  • 12 + x ≥ 3 (x - 6)
  • or, 12 + x ≥ 3x - 18
  • or, 12 + 18 ≥ 3x - x
  • or, 30 ≥ 2x
  • or, 30/2 ≥ x
  • or, 15 ≥ x
  • or, x ≤ 15

<u>Answer</u><u>:</u>

<em><u>x </u></em><em><u>≤</u></em><em><u> </u></em><em><u>1</u></em><em><u>5</u></em>

Hope you could get an idea from here.

Doubt clarification - use comment section.

7 0
3 years ago
Read 2 more answers
Sophia's school took a field trip. a total of 21 vehicles were needed for the trip. some students took the bus, and some student
Liono4ka [1.6K]
Let x be the number of buses, and y the number of cars.
\left \{ {{x+y=21} \atop {30x+4y=318}} \right.
We can solve for y in the first equation to get:
y=21-x
Now we can replace 21-x in our second equation, and solve for x:
30x+4(21-x)=318
30x+84-4x=318
26x=234
x= \frac{234}{26}
x=9

We can conclude that 9 buses were needed for the trip.
4 0
4 years ago
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