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2 years ago

If the constant term, c, in a trinomial axˆ2 + bx + c is positive, what do you know about the signs of its factors?

Mathematics

1 answer:

Gnom [1K]2 years ago

6 0

Answer:

They are either both positive or both negative

Step-by-step explanation:

If only one is negative, c will be negative as well.

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Open image to see question

Agata [3.3K]

Answer:

Step-by-step explanation:

To start off this problem, we are given that the line AB is equal to the line CD. In addition to that, we are given that the line EF equally intersects line AB and line CD. This provides us proof that angle AGH is equivalent to angle DHG. From this information, we can solve this problem relatively easily.

Lets work with this equation:

$80 = 5x$

Next, divide 80 by 5.

$\frac{80}{5} =x$

$16 = x$

This means that x is equal to 16.

7 0

3 years ago

Test the claim that the mean GPA of Orange Coast students is smaller than the mean GPA of Coastline students at the 0.005 signif

algol [13]

Answer:

a) F. H 0 : μ O ≥ μ C

H 1 : μ O < μ C

b) B. two-tailed

d) $t=\frac{(2.91-2.96)-0}{\sqrt{\frac{0.05^2}{60}+\frac{0.03^2}{60}}}}=-6.64$

e) $p_v =P(t_{118}$

f) B. Reject the null hypothesis

Step-by-step explanation:

Information provided

$\bar X_{O}=2.91$ represent the mean for the Orange Coast

$\bar X_{C}=2.96$ represent the mean for the Coastline

$s_{O}=0.05$ represent the sample standard deviation for Orange Coast

$s_{C}=0.03$ represent the sample standard deviation for Coastline

$n_{O}=60$ sample size for Orange Coast

$n_{C}=60$ sample size for Coastline

$\alpha=0.005$ Significance level provided

t would represent the statistic

Part a

For this case we want to test the claim that the mean GPA of Orange Coast students is smaller than the mean GPA of Coastline students

Null hypothesis: $\mu_{O} \geq \mu_{C}$

Alternative hypothesis: $\mu_{O} < \mu_{C}$

F. H 0 : μ O ≥ μ C

H 1 : μ O < μ C

Part b

For this case we need to conduct a left tailed test.

B. two-tailed

Part d

The statistic is given by:

$t=\frac{(\bar X_{O}-\bar X_{C})-\Delta}{\sqrt{\frac{s^2_{O}}{n_{O}}+\frac{s^2_{C}}{n_{C}}}}$ (1)

And the degrees of freedom are given by $df=n_1 +n_2 -2=60+60-2=118$

Replacing the info we got:

$t=\frac{(2.91-2.96)-0}{\sqrt{\frac{0.05^2}{60}+\frac{0.03^2}{60}}}}=-6.64$

Part e

We can calculate the p value with this probability:

$p_v =P(t_{118}$

Part f

Since the p value is a very low value compared to the significance level given of 0.005 we can reject the null hypothesis.

B. Reject the null hypothesis

5 0

2 years ago

If the dimension of a square is 3 1/2 what would the perimeter be?

Eduardwww [97]

It would be 3 because in a half means like cut so what is in the middle between 2 and 4? 3 so that is correct

6 0

3 years ago

Read 2 more answers

In which figure is point G a centroid?

GaryK [48]

Hey, there is no picture???

4 0

3 years ago

Read 2 more answers

Scott Harris can invest $7,000 in a 1-year CD that earns interest at an annual rate of 4 percent compounded monthly. The amount

Tom [10]

Answer:

option A is answer.

Step-by-step explanation:

Amount of interest earned for compounded monthly for $1 = 1.040742

Amount of interest earned for compounded quarterly for $1= 1.040604

Difference for $1 = 1.040742 - 1.40604

=0.000138

Difference for $7000 = $7000x0.000138

= 0.966

or $0.96

8 0

3 years ago