I’ll mark brainliest

Equivalent to 13/5 A.2.4 B.2.45 C.2.55 D.2.6 NEED HELP ASAP!!!!

jek_recluse [69]

D is the answer because 13 goes into 5 twice and 3 Is left over multiply that by two to get 6/10 than that it's equivalent to .6 so it is 2.6

7 0

3 years ago

Fill in the blanks to complete the description of the track. The track has ____ sides of the square and the distance around ____

rjkz [21]

Answer:

Step-by-step explanation:

The track has four sides of the square and the distance around 2 complete circle(s)

8 0

3 years ago

At the beginning of the week, Naveen has 87 trading cards. On Monday, he gets 9 more. On Tuesday, he gives 16 away. On Wednesday

Zielflug [23.3K]

He has 87 cards then he gets 9 more which is 96, he then gives 16 away which is 80, then he is given 3 which is 83 he sells all 83 cards to the collector & the collector gives him $124.50 each card is worth $1.50

4 0

3 years ago

Read 2 more answers

Milk is a good source of many vitamins that can help us stay healthy. FDA recommends that the average vitamin A concentration fo

Lelechka [254]

Answer:

The degrees of freedom for this sample are 27.

The sample size to get a margin of error equal or less than 0.3656 is n=4450.

Step-by-step explanation:

The degrees of freedom for calculating the value of t are:

$df=n-1=28-1=27$

With 27 degrees of freedom and 95% confidence level, from a table we can get that the t-value is t=2.052.

The sample size to get a margin of error equal or less than 0.3656 can be calculated as:

$MOE=t\cdot s/\sqrt{n}\\\\n=\left(\dfrac{t\cdot s}{MOE}\right)^2=\left(\dfrac{2.052\cdot 11.8841}{0.3656}\right)^2=66.7^2\\\\\\n=4449.13\approx4450$

6 0

3 years ago

Each year, all final year students take a mathematics exam. It is hypothesised that the population mean score for this test is 1

Yuri [45]

Answer:

90% confidence interval for the population mean test score is [95.40 , 106.59]

Step-by-step explanation:

We are given that the population mean score for mathematics test is 115. It is known that the population standard deviation of test scores is 17.

Also, a random sample of 25 students take the exam. The mean score for this group is 101.

The, pivotal quantity for 90% confidence interval for the population mean test score is given by;

P.Q. = $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, X bar = sample mean = 101

$\sigma$ = population standard deviation

n = sample size = 25

So, 90% confidence interval for the population mean test score, $\mu$ is ;

P(-1.6449 < N(0,1) < 1.6449) = 0.90

P(-1.6449 < $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ < 1.6449) = 0.90

P(-1.6449 * $\frac{\sigma}{\sqrt{n} }$ < ${Xbar-\mu}$ < 1.6449 * $\frac{\sigma}{\sqrt{n} }$ ) = 0.90

P(X bar - 1.6449 * $\frac{\sigma}{\sqrt{n} }$ < $\mu$ < X bar + 1.6449 * $\frac{\sigma}{\sqrt{n} }$ ) = 0.90

90% confidence interval for $\mu$ = [ X bar - 1.6449 * $\frac{\sigma}{\sqrt{n} }$ , X bar + 1.6449 * $\frac{\sigma}{\sqrt{n} }$ ]

= [ 101 - 1.6449 * $\frac{17}{\sqrt{25} }$ , 10 + 1.6449 * $\frac{17}{\sqrt{25} }$ ]

= [95.40 , 106.59]

Therefore, 90% confidence interval for the population mean test score is [95.40 , 106.59] .

7 0

3 years ago