So let's take a peek at both's ages, keep in mind, every year, is 1year added to Irene and 1year added to Fred
so... if we look at their ages

notice, Fred is always 40years older than Irene
thus, whatever age Irene is, let's say "i", then Fred is " i + 40 "
now, when is Fred 5 times Irene's age or 5*i or 5i? well,
f = fred's age i = irene's age
f = i + 40
now if f = 5i
5i = i + 40 <--- solve for "i" to see how old Irene was then
Answer:
5
Explanation:
1/4 of 12 = 3
2 + 3 = 5
sara speed is half of Jeanette's so if jeanette ran 7 miles then her walking speed is 3.5MPH and sense she is 7 miles ahed sara is 10.5 miles behind... 3.5MPH which is jeanette speed is double than sara so 3.5/2 is 1.75MPH... Saras walking speed is 1.75MPH
here is your ans have a nice day
4000 (4x10^3) times 400 (4x10^2) is equal to 16x10^5 ( 1,600,000)