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77julia77 [94]
2 years ago
10

HELP PLEASE TEST DUE, SHOW WORK PLEASE

Mathematics
1 answer:
yuradex [85]2 years ago
4 0
If you can give me more information on this I could help you a bit more respond.
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Can somone answer this
Sunny_sXe [5.5K]

Answer:

$618

Step-by-step explanation:

$1854 divided by 18 months = $103 per month

$103 x 12 months = $1236 paid in one year.

$1854originally owed - $1236 paid in a year = $618 still owed after one year of payments.

8 0
2 years ago
Read 2 more answers
An array showing the factor pair of three and 6 would have 3 rows of 6 objects. True? Or False?
JulsSmile [24]

Answer:

false

Step-by-step explanation:

3 0
3 years ago
Jay is paid £2000 each month. He saves 6% of the £2000 each month. How many months will it take Jay to save £480? ​
BARSIC [14]

Answer:

4 months

Step-by-step explanation:

(2000 *6)/100 = 120

120x = 480

X = 480/120

X = 4 months

4 0
2 years ago
(50 POINTS) Express each sum using summation notation.
vesna_86 [32]

14: a

1

=

39

/2                              0.25               313%        16%

15:     54

4 0
2 years ago
Directions: for questions 1 through 4, find the diagonal length of each solid figure.
Alex787 [66]
\text{The length of the diagonal is }11.2\text{ mm}

Here, we want to find the diagonal of the given solid

To do this, we need the appropriate triangle

Firstly, we need the diagonal of the base

To get this, we use Pythagoras' theorem for the base

The other measures are 6 mm and 8 mm

According ro Pythagoras' ; the square of the hypotenuse equals the sum of the squares of the two other sides

Let us have the diagonal as l

Mathematically;

\begin{gathered} l^2=6^2+8^2 \\ l^2\text{ = 36 + 64} \\ l^2\text{ =100} \\ l\text{ = }\sqrt[]{100} \\ l\text{ = 10 mm} \end{gathered}

Now, to get the diagonal, we use the triangle with height 5 mm and the base being the hypotenuse we calculated above

Thus, we calculate this using the Pytthagoras' theorem as follows;

\begin{gathered} d^2=5^2+10^2 \\ d^2\text{ = 25 + 100} \\ d^2\text{ = 125} \\ d\text{ = }\sqrt[]{125} \\ d\text{ = }11.2\text{ mm} \end{gathered}

7 0
11 months ago
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