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3 years ago

What 2 numbers can I add to the table to still have a function x: 6,3,9,7 y: 6,8,12,8 numbers I can use are: 3,6,7,8,9,12

Mathematics

1 answer:

Mrrafil [7]3 years ago

6 0

9514 1404 393

Answer:

8, 12

Step-by-step explanation:

The x-values of a function cannot repeat. That is, the x-values already in the table, {3, 6, 7, 9}, cannot be used again. Any added x-values must be different from these if your relation is to remain a function.

Of the choices offered, only 8 and 12 can be used for added x-values.

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Leyla drops a penny from a height of 150 m. How long will it take the penny to hit the ground? Use the formula h(t)=−4.9t^2+vt+h

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3 years ago

Read 2 more answers

Determine whether is a right triangle for the given vertices. Explain. Q(7, –10), R(–3, 0), S(9, –8)

andriy [413]

Answer:

Yes, It is a right triangle for the given vertices.

Step-by-step explanation:

Given:

Q(7, –10),

R(–3, 0),

S(9, –8)

To Find:

determine whether is a rig ht triangle for the given vertices = ?

Solution:

QR= $\sqrt{(-3-7)^2+(0-(-10))^2}$

QR= $\sqrt{(-10)^2+(10)^2}$

QR= $\sqrt{100+100}$

QR= $\sqrt{200}$ --------------------------(1)

QR=14.142136

RS= $\sqrt{(9-(-3))^2+(-8-0)^2}$

RS= $\sqrt{(12)^2+(-8)^2}$

RS= $\sqrt{144+64}$

RS= $\sqrt{208}$ ---------------------------(2)

RS=14.422205

QS= $\sqrt{(7-9)^2+(-10-(-8))^2}$

QS= $\sqrt{(-2)^2+(-2)^2}$

QS= $\sqrt{4+4}$

QS= $\sqrt{8}$ -------------------------------------(3)

QS=2.828427

According to Pythagorean Theorem,

$RS^2 = QR^ +QS^2$

Substituting the values,

$(\sqrt{208})^2 = (\sqrt{200})^2 +(\sqrt{8})^2$

$208 = 200 +8$

208 = 208

Pythagorean theorem is satisfied. Hence it is a right triangle.

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