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2 years ago

What 2 numbers can I add to the table to still have a function x: 6,3,9,7 y: 6,8,12,8 numbers I can use are: 3,6,7,8,9,12

Mathematics

1 answer:

Mrrafil [7]2 years ago

6 0

9514 1404 393

Answer:

8, 12

Step-by-step explanation:

The x-values of a function cannot repeat. That is, the x-values already in the table, {3, 6, 7, 9}, cannot be used again. Any added x-values must be different from these if your relation is to remain a function.

Of the choices offered, only 8 and 12 can be used for added x-values.

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2 years ago

Stephen uses

34kurt

Answer:

13.75 servings or 13 ¾ servings

Step-by-step explanation:

This is the correct question

Stephen uses 2/25 kilograms of tofu in each serving of his famous tofu dish. He has 1 1/10 kilograms of tofu.

To get answer

We will have to divide the number of tofu required with the number of tofu own.

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3 years ago

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If y = 5x − 4, which of the following sets represents possible inputs and outputs of the function represented as ordered pairs?

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2 years ago

The length of the base edge of a pyramid with a regular hexagon base is represented as x. The height of the pyramid is 3 times l

sergij07 [2.7K]

Answer:

(a)

h=3x

(b)

$A=\frac{\sqrt{3} }{4} x^2$

(c)

$A=\frac{3\sqrt{3} }{2} x^2$

(d)

$V=\frac{3\sqrt{3} }{2} x^3$ units^3

Step-by-step explanation:

We are given a regular hexagon pyramid

Since, it is regular hexagon

so, value of edge of all sides must be same

The length of the base edge of a pyramid with a regular hexagon base is represented as x

so, edge of base =x

b=x

Let's assume each blank spaces as a , b , c, d

we will find value for each spaces

(a)

The height of the pyramid is 3 times longer than the base edge

so, height =3*edge of base

height=3x

h=3x

(b)

Since, it is in units^2

so, it is given to find area

we know that

area of equilateral triangle is

$=\frac{\sqrt{3} }{4} b^2$

h=3x

b=x

now, we can plug values

$A=\frac{\sqrt{3} }{4} x^2$

(c)

we know that

there are six such triangles in the base of hexagon

So,

Area of base of hexagon = 6* (area of triangle)

Area of base of hexagon is

$=6\times \frac{\sqrt{3} }{4} x^2$

$=\frac{3\sqrt{3} }{2} x^2$

(d)

Volume=(1/3)* (Area of hexagon)*(height of pyramid)

now, we can plug values

Volume is

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3 years ago

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