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melamori03 [73]
3 years ago
11

Write the sentence as an equation.

Mathematics
2 answers:
GarryVolchara [31]3 years ago
8 0
250=h+54

tell me if you need me to solve it ! :)
icang [17]3 years ago
5 0

Answer:

250=h+54

additional:

h=196

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3 years ago
In a recent survey of 655 working Americans ages 25-34, the average weekly amount spent on lunch was 43.76 with standard deviati
klemol [59]

Answer:

Between 38.42 and 49.1.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean of 43.76, standard deviation of 2.67.

Between what two values will approximately 95% of the amounts be?

By the Empirical Rule, within 2 standard deviations of the mean. So

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Between 38.42 and 49.1.

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2 years ago
What fraction is equivalent to - 3/2
Varvara68 [4.7K]

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6 0
2 years ago
From a random sample of 58 businesses, it is found that the mean time the owner spends on administrative issues each week is 21.
zzz [600]

Answer: (20.86, 22.52)

Step-by-step explanation:

Formula to find the confidence interval for population mean :-

\overline{x}\pm z^*\dfrac{\sigma}{\sqrt{n}}

, where \overline{x} = sample mean.

z*= critical z-value

n= sample size.

\sigma = Population standard deviation.

By considering the given question , we have

\overline{x}= 21.69

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n= 58

Using z-table, the critical z-value for 95% confidence = z* = 1.96

Then, 95% confidence interval for the amount of time spent on administrative issues will be :

21.69\pm (1.96)\dfrac{3.23}{\sqrt{58}}

=21.69\pm (1.96)\dfrac{1.7}{7.61577}

=21.69\pm (1.96)(0.223221)

\approx21.69\pm0.83

=(21.69-0.83,\ 21.69+0.83)=(20.86,\ 22.52)

Hence, the 95% confidence interval for the amount of time spent on administrative issues = (20.86, 22.52)

7 0
3 years ago
Find the slope of a line through the passing lines of (-7,-7) and (-3, 6)
sesenic [268]
Let's use the slope formula!

m = y2 - y1 / (x2 - x1)

m = 6 + 7 / (-3 + 7) = 13/4
3 0
3 years ago
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