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STatiana [176]
3 years ago
8

Fina a polynomial function of degree 3 with real coefficients that has -1,2,-4 as zeros

Mathematics
1 answer:
leonid [27]3 years ago
3 0

Answer:

f(x) = x³ + 3x² - 6x - 8

Step-by-step explanation:

given the zeros of a polynomial x = a, x = b, x = c then

(x - a), (x - b), (x - c) are the factors of the polynomial and f(x) is the product of the factors

here x = - 1, x = 2 and x = - 4 are the zeros, hence

(x + 1), (x - 2) and (x + 4) are the factors

f(x) = a(x + 1)(x - 2)(x + 4) ← a is a multiplier

let a = 1, then

f(x) = (x + 1)(x - 2)(x + 4)

     = (x² - x - 2)(x + 4)

     = x³ - x² - 2x + 4x² - 4x - 8

     = x³ + 3x² - 6x - 8


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25 ≥ 5u u = 5<br><br> True of false ( show work )
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3. ** Over the course of July, the high temperatures of 6 random days were collected. The data is 2 shown below. 84°F 92°F 79°F
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Given data:

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1 year ago
Line c has an equation of y=-3/4x-3. Line d is parallel to line c and passes through the points (-2, -2). What is the equation o
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Answer:

y = \frac{3}{4} x - \frac{7}{2}

Step-by-step explanation:

The equation of a line in slope- intercept form is

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