we need to get a common denominator
2/3 2/3 * 5/5 = 10/15
6 2/3 = 6 10/15 < 6 12/15
so 6 2/3 < 6 12 /15
The tangent of the angle gives the ratio of the height of the lighthouse to the boat's distance
.. tan(angle of depression) = (lighthouse height)/(boat distance)
Then the distance to the boat is
.. boat distance = (lighthouse height)/tan(angle of depression)
We want to find the difference between two distances, so
.. boat travel = (lighthouse height)*(1/tan(first angle) -1/(tan(second angle))
.. = (200 ft)*(1/tan(17°31') -1/tan(46°41'))
.. ≈ 445.10 ft
Answer:
how can someone solve dis?
Step-by-step explanation:
Answer:
x=4 y=1
x=4 y=4
Step-by-step explanation:
x=4 goes on plot 4
(4,f(4)) plot goes on 4 x, 4 and y, 4
hope this helps
Let
b-----------> the length side of the square box
h------------> the height of the box
SA---------> surface area of the box
we know that
[volume of the box]=b²*h
volume=256 in³
b²*h=256-------> h=256/b²-----> equation 1
surface area of the box=area of the base+perimeter of base*height
area of the base=b²
perimeter of the base=4*b
surface area=b²+(4*b)*h------> SA=b²+4*b*h-----> equation 2
substitute equation 1 in equation 2
SA=b²+4*b*[256/b²]-----> SA=b²+1024/b-----> SA=(b³+1024)/b
the answer is
the formula of the volume of the box is V=b²*h-----> 256=b²*h
the formula of the surface area of the box are
SA=b²+4*b*h
SA=(b³+1024)/b
